Try   HackMD

Dimension of the Cantor set

Question

One way to define the Cantor set is as follows:

C0=[0,1]C1=13C0(23+13C0)C2=13C1(23+13C1) Cn=13Cn1(23+13Cn1)

image

Finally, define

C=n=0Cn. See an illustration here.

Comparing

3C and
C
, what would you guess the ratio of their lengths is?

Experiments

You need: handout

  1. On the handout, mark the endpoints of each segment in ternary number.
  2. Is
    0.23
    in
    C
    ?
  3. Is
    0.113
    in
    C
    ?
  4. Try to draw
    3C
    .
  5. Compare it with
    C
    .

Intuition

If

I is an interval in
R
, then
3C
has
3
times the length of
I
.

If

I is a square in
R2
, then
3C
has
32
times the area of
I
.

If

I is a cube in
R3
, then
3C
has
33
times the volumn of
I
.

If

C has dimension
d
, then
3C
supposedly has
3d
times the "size" of
C
. As
3d=2
, it suggest that the dimension of
C
is
log320.631
. This number is called the fractal dimension .

More questions to think about

  1. Is
    0.023
    in
    C
    ?
  2. Is
    0.21233
    in
    C
    ?
  3. Is
    0.20
    in
    C
    ?
  4. Describe
    C
    in terms of ternary numbers.
  5. What is the "length" of
    C
    ?

Resources

  1. YouTube: Fractals are typically not self-similar by 3Blue1Brown