# An exact sequence bounded by zeros, the alternating sum of the ranks is 0
Note that for an exact sequence
\begin{equation}
0 \to X \to Y \to Z \to 0
\end{equation}
of finitely generated Abelian groups $X$, $Y$, $Z$, we have the result $\operatorname{rank}(Y) = \operatorname{rank}(X) + \operatorname{rank}(Z)$.
First. Decompose the exact sequence you start with into many short exact sequences, each one corresponding to the kernel and image of the maps in the first one.
For example, if $f: A \to B$ is a map, you can construct short exact sequences
\begin{equation}
0 \to \ker f \to A \to \operatorname{im} f \to 0.
\end{equation}
Later. The point of the hint was for you to use the observation provided by your notes themselves. Suppose that we have an exact complex
\begin{equation}
0 \xrightarrow{f_{-1}} X_0 \xrightarrow{f_0} X^1 \xrightarrow{f_1} X^2 \xrightarrow{f_2} \dots \xrightarrow{f_{n-1}} X_n \xrightarrow{f_n} 0
\end{equation}For each $i \in \{-1, \ldots, n\}$, we have the map $f_i: X_i \to X_{i+1}$ (letting $X_{-1} = X_{n+1} = 0$ for convenience) so we have a short exact sequence
\begin{equation}
0 \to \ker f_i \to X_i \to \operatorname{im} f_i \to 0.
\end{equation}
So, assuming we know that the rank is additive in short exact sequences, we have $\operatorname{rk} X_i = \operatorname{rk} \ker f_i + \operatorname{rk} \operatorname{im} f_i$.
Multiplying this by $(-1)^i$ and summing over $i$ we see then that $\sum_{i=-1}^{n} (-1)^i \operatorname{rk} X_i = \sum_{i=-1}^{n} (-1)^i \operatorname{rk} \ker f_i + \sum_{i=-1}^{n} (-1)^i \operatorname{rk} \operatorname{im} f_i.\quad$ (1)
Now, the original exact sequence being exact, we have $\ker f_{i+1} \cong \operatorname{im} f_i$ for all $i$, so of course $\operatorname{rk} \ker f_{i+1} = \operatorname{rk} \operatorname{im} f_i$ for all $i$. Using this in the right-hand side of (1) we easily see that, in fact,$\sum_{i=-1}^{n} (-1)^i \operatorname{rk} X_i = 0.$
# Summary of all content
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https://hackmd.io/ir8dZ4wBRyeiJ0rGKGx6uw
Introduction to the concept of a topological space and fundamental notions in space theory.
## 2. The Fundamental Group of the Circle
https://hackmd.io/8KLv8CWaTUqn-JmJUyu9iw
The content explores covering spaces, liftings, and the fundamental group in algebraic topology. It introduces concepts like evenly covered subsets, path lifting, and the fundamental group of the circle. Theorems discuss homomorphisms, induced maps, and properties of covering spaces.
## 3. Retractions and Fixed Points
https://hackmd.io/DBhjY3ltSOaAh-fFoaBWRQ
The concepts retractions, and theorems in algebraic topology.Including the no-retraction theorem for the unit disk, the Brouwer Fixed-Point Theorem, and the existence of points in $S^1$ where a nonvanishing vector field on $B^2$ points directly inward and outward.
## 4. The Fundamental Theorem of Algebra and The Borsuk-Ulam Theorem
https://hackmd.io/GYyCiy8XQzuCBk-bZ5hAug
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## 5. Deformation Retracts and Homotopy type
https://hackmd.io/cL7WVHUMSECDh-nfz-pQiw
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## 6. Compute some fundamental group
https://hackmd.io/fzxFI7l-Rf-TB5sWETu70Q
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## 7. Classification of Covering Spaces
https://hackmd.io/gXnf219QQi-Qnfip6cwpKA
The article talk about equivalence of Covering Spaces and the Universal Covering Space
## 8. Covering Transformations
https://hackmd.io/vfOStbdcTD2zkEsZehLg-g
It discusses covering transformations, normal subgroups, and the relation between the fundamental group and regular covering maps in algebraic topology.
## 9. Simplicial Homology
https://hackmd.io/GFUNUIdnTimgFg5jJ_hQmw
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## 10. Some application of homology
https://hackmd.io/IrgYSdekQxiKTRqYt-opTw
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## 11. Some application of Homology group (2)
https://hackmd.io/PSN3aPbKTI6fyS6wpGogEA
The text employs the Mayer–Vietoris Sequence to prove the Jordan Curve Theorem and elucidates the connection between the fundamental group and homology group. Additionally, it provides algorithms for homology applications.