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Lecture 14: Spectral Theorem for Bounded Operators
tags: 224a
The goal of this lecture is to prove the following important theorem of von Neumann. Theorem.(Spectral Theorem for Bounded Operators. If , there is a finite measure space , a function and a unitary such that
Continuous Functional Calculus
Let denote the Banach space of continuous functions on a compact set with the sup norm.
Theorem. (Continuous Functional Calculus) If there is a linear map with the following properties:
-homomorphism: .
Spectral Mapping:
Isometry: .
Eigenvector Mapping: If then .
Positivity: If then .
With the normalization that , the above is unique (in fact, assuming only (1) and continuity). We denote it by .
To prove the existence of such a mapping, we first show that it exists for the dense subspace of polynomial functions.
Lemma 1.(Spectral Mapping for Polynomials) If , . Proof. Reed and Simon VII.1
Lemma 2.(Isometry for Polynomials) If ,
The BLT theorem now implies that has a unique extension from to . Note that self-adjointness was used in two places: (1) the polynomial functions are dense in (2) for self-adjoint matrices. The theorem is simply not true without self-adjointness; consider the Jordan block with but .
Consequences and Spectral Measures
Theorem. If is self-adjoint is an isolated point in , then . Proof. Since is isolated, there is an such that and on . We also have and , so by the functional calculus, must be a nonzero orthogonal projection . Since , we have , whence .
A more substantial punch line is that the calculus yields a canonical way to associate a probability measure with a state. Given self-adjoint and any unit vector , consider the bounded linear map Notice that is positive because whenever by the functional calculus.
We now appeal to the fact that positive linear functionals on continuous functions always come from positive measures. Riesz-Markov Theorem. If is a positive, continuous linear functional, there is a unique finite positive Borel measure such that
Applying this to we obtain a canonical mapping . By pluggin in we see that , so it is a probability measure.
Cyclic Vectors
Defn. A vector is called cyclic if the closure of the span of is all of .
Thm. If has a cyclic vector , then there is an isometry such that Proof. Reed and Simon VII.2 Lemma 1.
The full spectral theorem follows because for any , can be decomposed into (possibly infinitely many) orthogonal invariant subspaces such that has a cyclic vector for every .