My Solution
The Key Idea for Solving This Coding Question
C++ Code
class Solution {
public:
vector<TreeNode *> delNodes(TreeNode *root, vector<int> &to_delete) {
unordered_set<int> deleteSet(to_delete.begin(), to_delete.end());
vector<TreeNode *> forest;
TreeNode *x = dfs(root, deleteSet, forest);
if (x != nullptr) {
forest.push_back(x);
}
return forest;
}
private:
TreeNode *dfs(TreeNode *root, unordered_set<int> &deleteSet, vector<TreeNode *> &forest) {
if (root == nullptr) {
return nullptr;
}
root->left = dfs(root->left, deleteSet, forest);
root->right = dfs(root->right, deleteSet, forest);
if (deleteSet.count(root->val) != 0) {
if (root->left != nullptr) {
forest.push_back(root->left);
}
if (root->right != nullptr) {
forest.push_back(root->right);
}
delete root;
return nullptr;
}
return root;
}
};
Time Complexity
Space Complexity
Miscellaneous