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997.Find the Town Judge

tags: Easy,Array,Hash Table,Graph

997. Find the Town Judge

題目描述

In a town, there are n people labeled from 1 to n. There is a rumor that one of these people is secretly the town judge.

If the town judge exists, then:

The town judge trusts nobody.

Everybody (except for the town judge) trusts the town judge.

There is exactly one person that satisfies properties 1 and 2.
You are given an array trust where trust[i] = [ai, bi] representing that the person labeled ai trusts the person labeled bi.

Return the label of the town judge if the town judge exists and can be identified, or return -1 otherwise.

範例

Example 1:

Input: n = 2, trust = [[1,2]]
Output: 2

Example 2:

Input: n = 3, trust = [[1,3],[2,3]]
Output: 3

Example 3:

Input: n = 3, trust = [[1,3],[2,3],[3,1]]
Output: -1

Constraints:

  • 1 <= n <= 1000
  • 0 <= trust.length <= 104
  • trust[i].length == 2
  • All the pairs of trust are unique.
  • ai != bi
  • 1 <= ai, bi <= n

解答

C++

class Solution { public: int findJudge(int n, vector<vector<int>>& trust) { vector<int> a(n), b(n); for (auto& t : trust) { a[t[0] - 1]++; b[t[1] - 1]++; } for (int i = 0; i < n; i++) { if (a[i] == 0 && b[i] == n - 1) { return i + 1; } } return -1; } };

Yen-Chi ChenTue, Jan 24, 2023

Reference

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