Easy
,Array
,Hash Table
,Graph
In a town, there are n
people labeled from 1
to n
. There is a rumor that one of these people is secretly the town judge.
If the town judge exists, then:
The town judge trusts nobody.
Everybody (except for the town judge) trusts the town judge.
There is exactly one person that satisfies properties 1 and 2.
You are given an array trust
where trust[i]
= [
Return the label of the town judge if the town judge exists and can be identified, or return -1
otherwise.
Example 1:
Input: n = 2, trust = [[1,2]]
Output: 2
Example 2:
Input: n = 3, trust = [[1,3],[2,3]]
Output: 3
Example 3:
Input: n = 3, trust = [[1,3],[2,3],[3,1]]
Output: -1
Constraints:
n
<= 1000trust.length
<= 104trust[i].length
== 2trust
are unique.n
class Solution {
public:
int findJudge(int n, vector<vector<int>>& trust) {
vector<int> a(n), b(n);
for (auto& t : trust) {
a[t[0] - 1]++;
b[t[1] - 1]++;
}
for (int i = 0; i < n; i++) {
if (a[i] == 0 && b[i] == n - 1) {
return i + 1;
}
}
return -1;
}
};
Yen-Chi ChenTue, Jan 24, 2023