785.Is Graph Bipartite?

tags: Medium,Graph,DFS,BFS

785. Is Graph Bipartite?

題目描述

There is an undirected graph with n nodes, where each node is numbered between 0 and n - 1. You are given a 2D array graph, where graph[u] is an array of nodes that node u is adjacent to. More formally, for each v in graph[u], there is an undirected edge between node u and node v. The graph has the following properties:

• There are no self-edges (graph[u] does not contain u).
• There are no parallel edges (graph[u] does not contain duplicate values).
• If v is in graph[u], then u is in graph[v] (the graph is undirected).
• The graph may not be connected, meaning there may be two nodes u and v such that there is no path between them.

A graph is bipartite if the nodes can be partitioned into two independent sets A and B such that every edge in the graph connects a node in set A and a node in set B.

Return true if and only if it is bipartite.

範例

Example 1:

Input: graph = [[1,2,3],[0,2],[0,1,3],[0,2]]
Output: false
Explanation: There is no way to partition the nodes into two independent sets such that every edge connects a node in one and a node in the other.

Example 2:

Input: graph = [[1,3],[0,2],[1,3],[0,2]]
Output: true
Explanation: We can partition the nodes into two sets: {0, 2} and {1, 3}.

Constraints:

• graph.length == n
• 1 <= n <= 100
• 0 <= graph[u].length < n
• 0 <= graph[u][i] <= n - 1
• graph[u] does not contain u.
• All the values of graph[u] are unique.
• If graph[u] contains v, then graph[v] contains u.

解答

Python

class Solution:
    def isBipartite(self, graph: List[List[int]]) -> bool:
        n = len(graph)
        colors = [0] * n
        
        def dfs(node, color = 1):
            if colors[node] != 0:
                return colors[node] == color
            colors[node] = color
            for nei in graph[node]:
                if not dfs(nei, -color):
                    return False
            return True
        
        for i in range(n):
            if colors[i] == 0:
                if not dfs(i):
                    return False
        return True

Yen-Chi ChenSat, May 20, 2023

Reference

Bipartite Graph

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