[673. Number of Longest Increasing Subsequence](https://leetcode.com/problems/number-of-longest-increasing-subsequence/) ### 題目描述 Given an integer array `nums`, return *the number of longest increasing subsequences*. **Notice** that the sequence has to be **strictly** increasing. ### 範例 **Example 1:** ``` Input: nums = [1,3,5,4,7] Output: 2 Explanation: The two longest increasing subsequences are [1, 3, 4, 7] and [1, 3, 5, 7]. ``` **Example 2:** ``` Input: nums = [2,2,2,2,2] Output: 5 Explanation: The length of the longest increasing subsequence is 1, and there are 5 increasing subsequences of length 1, so output 5. ``` **Constraints**: * 1 <= `nums.length` <= 2000 * -10^6^ <= `nums[i]` <= 10^6^ ### 解答 #### Python ```python= class Solution: def findNumberOfLIS(self, nums: List[int]) -> int: N = len(nums) d = [1] * N c = [1] * N for j in range(1, N): for i in range(j): if nums[i] < nums[j]: if d[i] + 1 > d[j]: d[j] = d[i] + 1 c[j] = c[i] elif d[i] + 1 == d[j]: c[j] += c[i] L = max(d) return sum(c[i] for i in range(N) if d[i] == L) ``` > [name=Yen-Chi Chen][time=Fri, Jul 21, 2023] ### Reference [回到題目列表](https://hackmd.io/@Marsgoat/leetcode_every_day)