Easy
,Array
,Greedy
You have a long flowerbed in which some of the plots are planted, and some are not. However, flowers cannot be planted in adjacent plots.
Given an integer array flowerbed
containing 0
's and 1
's, where 0
means empty and 1
means not empty, and an integer n
, return if n
new flowers can be planted in the flowerbed
without violating the no-adjacent-flowers rule.
Example 1:
Input: flowerbed = [1,0,0,0,1], n = 1
Output: true
Example 2:
Input: flowerbed = [1,0,0,0,1], n = 2
Output: false
Constraints:
flowerbed.length
<= 2 * 104flowerbed[i]
is 0 or 1.flowerbed
.n
<= flowerbed.length
class Solution:
def canPlaceFlowers(self, flowerbed: List[int], n: int) -> bool:
cnt = 0
for i in range(len(flowerbed)):
if flowerbed[i] == 0:
empty_left_plot = (i == 0) or (flowerbed[i - 1] == 0)
empty_right_plot = (i == len(flowerbed) - 1) or (flowerbed[i + 1] == 0)
if empty_left_plot and empty_right_plot:
flowerbed[i] = 1
cnt += 1
if cnt >= n:
return True
return cnt >= n
Ron ChenMon, Mar 20, 2023
function canPlaceFlowers(flowerbed, n) {
let count = 0;
for (let i = 0; i < flowerbed.length; i++) {
if (!flowerbed[i - 1] && !flowerbed[i] && !flowerbed[i + 1]) {
count++;
flowerbed[i] = 1;
}
}
if (count >= n) return true;
return false;
}
MarsgoatMon, Mar 20, 2023