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446.Arithmetic Slices II - Subsequence

tags: Hard,Array,DP

446. Arithmetic Slices II - Subsequence

題目描述

Given an integer array nums, return the number of all the arithmetic subsequences of nums.

A sequence of numbers is called arithmetic if it consists of at least three elements and if the difference between any two consecutive elements is the same.

  • For example, [1, 3, 5, 7, 9], [7, 7, 7, 7], and [3, -1, -5, -9] are arithmetic sequences.
  • For example, [1, 1, 2, 5, 7] is not an arithmetic sequence.

A subsequence of an array is a sequence that can be formed by removing some elements (possibly none) of the array.

  • For example, [2,5,10] is a subsequence of [1,2,1,2,4,1,5,10].

The test cases are generated so that the answer fits in 32-bit integer.

範例

Example 1:

Input: nums = [2,4,6,8,10]
Output: 7
Explanation: All arithmetic subsequence slices are:
[2,4,6]
[4,6,8]
[6,8,10]
[2,4,6,8]
[4,6,8,10]
[2,4,6,8,10]
[2,6,10]

Example 2:

Input: nums = [7,7,7,7,7]
Output: 16
Explanation: Any subsequence of this array is arithmetic.

Constraints:

  • 1 <= nums.length <= 1000
  • 231
    <= nums[i] <=
    2311

解答

C++

class Solution { public: int numberOfArithmeticSlices(vector<int>& nums) { int n = nums.size(); vector<unordered_map<long long, int>> dp(n); int ans = 0; for (int i = 0; i < n; i++) { for (int j = i-1; j >= 0; j--) { long long diff = (long long)nums[i] - (long long)nums[j]; ans += dp[j][diff]; dp[i][diff] += dp[j][diff] + 1; } } return ans; } };

Yen-Chi ChenSun, Nov 27, 2022 8:49 PM

Python

class Solution: def numberOfArithmeticSlices(self, nums: List[int]) -> int: n = len(nums) dp = [defaultdict(int) for _ in range(n)] ans = 0 for i in range(1, n): for j in range(i): diff = nums[i] - nums[j] ans += dp[j][diff] dp[i][diff] += dp[j][diff] + 1 return ans

Yen-Chi ChenSun, Nov 27, 2022 8:49 PM

Time:

O(n2)
Extra Space:
O(n2)

Reference

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