2305. Fair Distribution of Cookies

題目描述

You are given an integer array cookies, where cookies[i] denotes the number of cookies in the i^th bag. You are also given an integer k that denotes the number of children to distribute all the bags of cookies to. All the cookies in the same bag must go to the same child and cannot be split up.

The unfairness of a distribution is defined as the maximum total cookies obtained by a single child in the distribution.

Return the minimum unfairness of all distributions.

範例

Example 1:

Input: cookies = [8,15,10,20,8], k = 2
Output: 31
Explanation: One optimal distribution is [8,15,8] and [10,20]
- The 1st child receives [8,15,8] which has a total of 8 + 15 + 8 = 31 cookies.
- The 2nd child receives [10,20] which has a total of 10 + 20 = 30 cookies.
The unfairness of the distribution is max(31,30) = 31.
It can be shown that there is no distribution with an unfairness less than 31.

Example 2:

Input: cookies = [6,1,3,2,2,4,1,2], k = 3
Output: 7
Explanation: One optimal distribution is [6,1], [3,2,2], and [4,1,2]
- The 1st child receives [6,1] which has a total of 6 + 1 = 7 cookies.
- The 2nd child receives [3,2,2] which has a total of 3 + 2 + 2 = 7 cookies.
- The 3rd child receives [4,1,2] which has a total of 4 + 1 + 2 = 7 cookies.
The unfairness of the distribution is max(7,7,7) = 7.
It can be shown that there is no distribution with an unfairness less than 7.

Constraints:

• 2 <= cookies.length <= 8
• 1 <= cookies[i] <= 10⁵
• 2 <= k <= cookies.length

解答

Javascript

function distributeCookies(cookies, k) {
  const distributions = new Array(k).fill(0);
  let min = Infinity;

  cookies.sort((a, b) => b - a);

  function backtrack(index) {
    if (index == cookies.length) {
      min = Math.min(min, Math.max(...distributions));
      return;
    }

    const visited = new Set();
    for (let i = 0; i < k; i++) {
      if (visited.has(distributions[i])) continue;
      visited.add(distributions[i]);

      distributions[i] += cookies[index];
      if (distributions[i] <= min) backtrack(index + 1);
      distributions[i] -= cookies[index];
    }
  }

  backtrack(0);

  return min;
}

抄答案的backtracking，本來看到還以為這題是用binary search解
MarsgoatWed, July 5, 2023

Reference

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