2256.Minimum Average Difference === ###### tags: `Medium`,`Array`,`Prefix Sum` [2256. Minimum Average Difference](https://leetcode.com/problems/minimum-average-difference/) ### 題目描述 You are given a **0-indexed** integer array `nums` of length `n`. The **average difference** of the index `i` is the **absolute difference** between the average of the **first** `i + 1` elements of `nums` and the average of the **last** `n - i - 1` elements. Both averages should be **rounded down** to the nearest integer. Return *the index with the **minimum average difference***. If there are multiple such indices, return the **smallest** one. Note: * The **absolute difference** of two numbers is the absolute value of their difference. * The **average** of `n` elements is the **sum** of the `n` elements divided (**integer division**) by `n`. * The average of `0` elements is considered to be `0`. ### 範例 **Example 1:** ``` Input: nums = [2,5,3,9,5,3] Output: 3 Explanation: - The average difference of index 0 is: |2 / 1 - (5 + 3 + 9 + 5 + 3) / 5| = |2 / 1 - 25 / 5| = |2 - 5| = 3. - The average difference of index 1 is: |(2 + 5) / 2 - (3 + 9 + 5 + 3) / 4| = |7 / 2 - 20 / 4| = |3 - 5| = 2. - The average difference of index 2 is: |(2 + 5 + 3) / 3 - (9 + 5 + 3) / 3| = |10 / 3 - 17 / 3| = |3 - 5| = 2. - The average difference of index 3 is: |(2 + 5 + 3 + 9) / 4 - (5 + 3) / 2| = |19 / 4 - 8 / 2| = |4 - 4| = 0. - The average difference of index 4 is: |(2 + 5 + 3 + 9 + 5) / 5 - 3 / 1| = |24 / 5 - 3 / 1| = |4 - 3| = 1. - The average difference of index 5 is: |(2 + 5 + 3 + 9 + 5 + 3) / 6 - 0| = |27 / 6 - 0| = |4 - 0| = 4. The average difference of index 3 is the minimum average difference so return 3. ``` **Example 2:** ``` Input: nums = [0] Output: 0 Explanation: The only index is 0 so return 0. The average difference of index 0 is: |0 / 1 - 0| = |0 - 0| = 0. ``` **Constraints**: * 1 <= `nums.length` <= 10^5^ * 0 <= `nums[i]` <= 10^5^ ### 解答 #### Python ```python= class Solution: def minimumAverageDifference(self, nums: List[int]) -> int: if len(nums) <= 1: return 0 current_ans = [-1,1000000000] whole_array_sum = sum(nums) firstksum = 0 #print(nums) for idx, v in enumerate(nums): firstksum += v if idx == len(nums)-1: cur = abs( whole_array_sum/len(nums) ) else: cur = abs( floor(firstksum/(idx+1)) - floor( (whole_array_sum - firstksum)/(len(nums)-idx-1)) ) #print(cur, firstksum, idx+1, whole_array_sum - firstksum, len(nums)-idx-1) if cur < current_ans[1]: current_ans = [idx, cur] return current_ans[0] ``` > [name=玉山] [time= Dec 5, 2022] #### Javascript ```javascript= function minimumAverageDifference(nums) { let leftSum = 0; let rightSum = 0; for (let i = 0; i < nums.length; i++) { rightSum += nums[i]; } let minimum = Infinity; let index = 0; for (let i = 0; i < nums.length; i++) { leftSum += nums[i]; rightSum -= nums[i]; const miniAvgDiff = Math.abs(~~(leftSum / (i + 1)) - ~~(rightSum / Math.max(1, nums.length - 1 - i))); if (miniAvgDiff < minimum) { minimum = miniAvgDiff; index = i; } } return index; } ``` > [name=Marsgoat] [time= Dec 5, 2022] ### Reference [回到題目列表](https://hackmd.io/@Marsgoat/leetcode_every_day)