Medium
,Graph
1557. Minimum Number of Vertices to Reach All Nodes
Given a directed acyclic graph, with n
vertices numbered from 0
to n-1
, and an array edges
where edges[i]
= [
Find the smallest set of vertices from which all nodes in the graph are reachable. It's guaranteed that a unique solution exists.
Notice that you can return the vertices in any order.
Example 1:
Input: n = 6, edges = [[0,1],[0,2],[2,5],[3,4],[4,2]]
Output: [0,3]
Explanation: It's not possible to reach all the nodes from a single vertex. From 0 we can reach [0,1,2,5]. From 3 we can reach [3,4,2,5]. So we output [0,3].
Example 2:
Input: n = 5, edges = [[0,1],[2,1],[3,1],[1,4],[2,4]]
Output: [0,2,3]
Explanation: Notice that vertices 0, 3 and 2 are not reachable from any other node, so we must include them. Also any of these vertices can reach nodes 1 and 4.
Constraints:
n
<= 105edges.length
<= min(105, n * (n - 1) / 2)edges[i].length
== 2n
class Solution:
def findSmallestSetOfVertices(self, n: int, edges: List[List[int]]) -> List[int]:
return list(set(range(n)) - set(to for _, to in edges))
Yen-Chi ChenThu, May 18, 2023
function findSmallestSetOfVertices(n, edges) {
const set = new Set();
for (const [from, to] of edges) {
set.add(to);
}
const result = [];
for (let i = 0; i < n; i++) {
if (!set.has(i)) result.push(i);
}
return result;
}
這題直接用Set來記錄就行了,讓我想到1579題,當時天真的以為用Set就可以ㄏㄏ
MarsgoatThu, May 18, 2023