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1557.Minimum Number of Vertices to Reach All Nodes

tags: Medium,Graph

1557. Minimum Number of Vertices to Reach All Nodes

題目描述

Given a directed acyclic graph, with n vertices numbered from 0 to n-1, and an array edges where edges[i] = [

fromi,
toi
] represents a directed edge from node
fromi
to node
toi
.

Find the smallest set of vertices from which all nodes in the graph are reachable. It's guaranteed that a unique solution exists.

Notice that you can return the vertices in any order.

範例

Example 1:

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Input: n = 6, edges = [[0,1],[0,2],[2,5],[3,4],[4,2]]
Output: [0,3]
Explanation: It's not possible to reach all the nodes from a single vertex. From 0 we can reach [0,1,2,5]. From 3 we can reach [3,4,2,5]. So we output [0,3].

Example 2:

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Input: n = 5, edges = [[0,1],[2,1],[3,1],[1,4],[2,4]]
Output: [0,2,3]
Explanation: Notice that vertices 0, 3 and 2 are not reachable from any other node, so we must include them. Also any of these vertices can reach nodes 1 and 4.

Constraints:

  • 2 <= n <= 105
  • 1 <= edges.length <= min(105, n * (n - 1) / 2)
  • edges[i].length == 2
  • 0 <=
    fromi
    ,
    toi
    < n
  • All pairs (
    fromi
    ,
    toi
    ) are distinct.

解答

Python

class Solution: def findSmallestSetOfVertices(self, n: int, edges: List[List[int]]) -> List[int]: return list(set(range(n)) - set(to for _, to in edges))

Yen-Chi ChenThu, May 18, 2023

Javascript

function findSmallestSetOfVertices(n, edges) { const set = new Set(); for (const [from, to] of edges) { set.add(to); } const result = []; for (let i = 0; i < n; i++) { if (!set.has(i)) result.push(i); } return result; }

這題直接用Set來記錄就行了,讓我想到1579題,當時天真的以為用Set就可以ㄏㄏ
MarsgoatThu, May 18, 2023

Reference

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