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1539.Kth Missing Positive Number

1539. Kth Missing Positive Number

題目描述

Given an array arr of positive integers sorted in a strictly increasing order, and an integer k.

Return the kth positive integer that is missing from this array.

範例

Example 1:

Input: arr = [2,3,4,7,11], k = 5
Output: 9
Explanation: The missing positive integers are [1,5,6,8,9,10,12,13,...]. The 5th missing positive integer is 9.

Example 2:

Input: arr = [1,2,3,4], k = 2
Output: 6
Explanation: The missing positive integers are [5,6,7,...]. The 2nd missing positive integer is 6.

Constraints:

  • 1 <= arr.length <= 1000
  • 1 <= arr[i] <= 1000
  • 1 <= k <= 1000
  • arr[i] < arr[j] for 1 <= i < j <= arr.length

Follow up:

Could you solve this problem in less than O(n) complexity?

解答

Python

class Solution: def findKthPositive(self, arr: List[int], k: int) -> int: def feasible(mid) -> bool: return arr[mid] - mid - 1 < k l, r = 0, len(arr) while l < r: mid = l + (r - l) // 2 if feasible(mid): l = mid + 1 else: r = mid return l + k

Ron ChenMon, Mar 6, 2023

Javascript

function findKthPositive(arr, k) { let left = 0; let right = arr.length - 1; let missing = 0; while (left <= right) { const mid = ~~((left + right) / 2); missing = arr[mid] - mid - 1; if (missing < k) { left = mid + 1; } else { right = mid - 1; } } return left + k; }

學習了,本來還暴力解,不過也是會過ㄎㄎ
MarsgoatMon, Mar 6, 2023

Reference

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