Easy
,Math
1523. Count Odd Numbers in an Interval Range
Given two non-negative integers low
and high
. Return the count of odd numbers between low
and high
(inclusive).
Example 1:
Input: low = 3, high = 7
Output: 3
Explanation: The odd numbers between 3 and 7 are [3,5,7].
Example 2:
Input: low = 8, high = 10
Output: 1
Explanation: The odd numbers between 8 and 10 are [9].
Constraints:
low
<= high
<= 109
function countOdds(low, high) {
if (low % 2 === 0 && high % 2 === 0) return (high - low) / 2;
return ~~((high - low) / 2) + 1;
}
沒記錯好像是programiming skills 1第一天的題目
跟吉神學習惹 (看下面那個)
Marsgoat Feb 13, 2023
var countOdds = function(low, high) {
return Math.floor((high + 1) / 2) - Math.floor(low / 2);
};
Yen-Chi ChenMon, Feb 13, 2023
[1, high]之間的奇數數量 - [1, low-1]之間的奇數數量
class Solution {
public:
int countOdds(int low, int high) {
return (high + 1) / 2 - low / 2;
}
};
Yen-Chi ChenMon, Feb 13, 2023
class Solution:
def countOdds(self, low: int, high: int) -> int:
return (high - low) // 2 + (low % 2 == 1 or high % 2 == 1)
Ron Chen Feb 13, 2023
class Solution:
def countOdds(self, low: int, high: int) -> int:
return (high + 1) // 2 - low // 2
Yen-Chi ChenMon, Feb 13, 2023
public class Solution {
public int CountOdds(int low, int high) {
return (high - low) / 2 + ((low | high) & 1);
}
}
JimFeb 13, 2023