1470.Shuffle the Array
===

###### tags: `Easy`,`Array`

[1470. Shuffle the Array](https://leetcode.com/problems/shuffle-the-array/)

### 題目描述

Given the array `nums` consisting of `2n` elements in the form `[x1,x2,...,xn,y1,y2,...,yn]`.

*Return the array in the form* `[x1,y1,x2,y2,...,xn,yn]`.

### 範例

**Example 1:**

Input: nums = [2,5,1,3,4,7], n = 3
Output: [2,3,5,4,1,7] 
Explanation: Since x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 then the answer is [2,3,5,4,1,7].

**Example 2:**

Input: nums = [1,2,3,4,4,3,2,1], n = 4
Output: [1,4,2,3,3,2,4,1]

**Example 3:**

Input: nums = [1,1,2,2], n = 2
Output: [1,2,1,2]

**Constraints**:

* 1 <= `n` <= 500
* `nums.length` == `2n`
* 1 <= `nums[i]` <= 10^3^

### 解答
#### Javascript

function shuffle(nums, n) {
  const result = [];
  for (let i = 0; i < n; i++) {
    result.push(nums[i]);
    result.push(nums[i + n]);
  }

  return result;
}

> [name=Marsgoat][time= Feb 6, 2023]

#### Python

class Solution:
    def shuffle(self, nums: List[int], n: int) -> List[int]:
        return [j for i in zip(nums[:n], nums[n:]) for j in i]

> [name=Ron Chen][time= Feb 6, 2023]

class Solution:
    def shuffle(self, nums: List[int], n: int) -> List[int]:
        return list(chain(*zip(nums[:n],nums[n:])))

> [name=Yen-Chi Chen][time=Mon, Feb 6, 2023]

class Solution:
    def shuffle(self, nums: List[int], n: int) -> List[int]:
        return [nums[(i & 1) * n + i // 2] for i in range(n * 2)]

> [name=Yen-Chi Chen][time=Mon, Feb 6, 2023]

### Reference

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