Easy
,Tree
,DFS
,BFS
,Binary Tree
Given the roots of two binary trees p
and q
, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.
Example 1:
Input: p = [1,2,3], q = [1,2,3]
Output: true
Example 2:
Input: p = [1,2], q = [1,null,2]
Output: false
Example 3:
Input: p = [1,2,1], q = [1,1,2]
Output: false
Constraints:
[0, 100]
.Node.val
<= 104
function isSameTree(p, q) {
if (p === null && q === null) return true;
if (p === null || q === null) return false;
if (p.val !== q.val) return false;
return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
}
Marsgoat Jan 10, 2023
class Solution:
def isSameTree(self, p: Optional[TreeNode], q: Optional[TreeNode]) -> bool:
if not p and not q: return True
if not p or not q: return False
return p.val == q.val and self.isSameTree(p.left, q.left) and self.isSameTree(p.right, q.right)
Ron ChenTue, Jan 10, 2023
分享討論區中發現的一行解法
def isSameTree(self, p, q):
return p and q and p.val == q.val and all(map(self.isSameTree, (p.left, p.right), (q.left, q.right))) or p is q
public class Solution {
public bool IsSameTree(TreeNode p, TreeNode q) {
if (p == null && q == null) return true;
if (p == null || q == null) return false;
if (p.val != q.val) return false;
return IsSameTree(p.left, q.left) && IsSameTree(p.right, q.right);
}
}
JimTue, Jan 10, 2023