---
# System prepended metadata

title: 2634.Filter Elements from Array
tags: [Array, leetCode]

---

# 2634.Filter Elements from Array

###### tags:`Array` | `leetCode`
<font color="#01AE9A" background="E1F3F0">`easy`</font>
 
### 題目
Given an integer array arr and a filtering function fn, return a new array with a fewer or equal number of elements.

The returned array should only contain elements where fn(arr[i], i) evaluated to a truthy value.

Please solve it without the built-in Array.filter method.

`returnedArray[i] = fn(arr[i], i)`.

Please solve it without the built-in `Array.map` method.
### Example
```javascript=
Input: arr = [0,10,20,30], fn = function greaterThan10(n) { return n > 10; }
Output: [20,30]
Explanation:
const newArray = filter(arr, fn); // [20, 30]
The function filters out values that are not greater than 10
```
```javascript=
Input: arr = [1,2,3], fn = function firstIndex(n, i) { return i === 0; }
Output: [1]
Explanation:
fn can also accept the index of each element
In this case, the function removes elements not at index 0
```
```javascript=
Input: arr = [-2,-1,0,1,2], fn = function plusOne(n) { return n + 1 }
Output: [-2,0,1,2]
Explanation:
Falsey values such as 0 should be filtered out
```

### Constraints
- `0 <= arr.length <= 1000`
- `-109 <= arr[i] <= 109`

---
### 解題邏輯
這題函式接受一個數字 `arr`和一個 `callback function`當作參數

```javascript=
var filter = function(arr, fn) {
  let newArray =[]
  for(let i = 0;i <arr.length;i++){
    if(fn(arr[i], i)){
      newArray.push(arr[i])
    }
  }
   return newArray
};
```
![](https://hackmd.io/_uploads/rJpSGCv43.png)

跟 [Day4](https://hackmd.io/Zb9OCwYdQgiv_JSRDxTH8w)類似，只不過這題是用 arr 裡面的數字去跑 fn ,true 才把數字 push 到 newArry 裏面