## 流程圖

st=>start: 開始
ed=>end: 結束
mg0=>operation: msg = "是潤年"
mg1=>operation: msg = "是平年"
io0=>inputoutput: 給定一個正整數yr
op0=>operation: msg = yr.toString() + msg
cond0=>condition: yr為偶數?
cond1=>condition: yr可以被4整除?
cond2=>condition: yr可以被100整除?
cond3=>condition: yr可以被400整除?

st->io0->cond0

cond0(yes)->cond1
cond0(no)->mg1->op0->ed
cond1(yes)->cond2
cond1(no)->mg1
cond2(yes)->cond3
cond2(no)->mg0
cond3(yes)->mg0->op0->ed
cond3(no)->mg1

### CSMA/CD作業

st=>start: 開始
ed0=>end: 送出成功
ed1=>end: 放棄傳送
temp=>operation: CSMA/CD
mg0=>operation: 延遲9.6μs送出資料框
mg1=>operation: 延遲一段時間
mg2=>operation: 演算法算出隨機等待時間
mg3=>operation: 等待一小段的隨機時間
cond0=>condition: 傾聽網路是否空閒
cond1=>condition: 發生碰撞
cond2=>condition: 嘗試未達15次
op0=>operation: 0

st->temp->cond0

cond0(yes)->mg0->cond1
cond0(no)->mg1(top)->temp
cond1(yes)->cond2
cond1(no)->ed0
cond2(no)->ed1
cond2(yes)->mg2->mg3->temp

## 計程車

st=>start: 開始
ed=>end: 結束
mg0=>operation: M0 = 85
mg1=>operation: M0 = 85+5*C
mg2=>operation: 跳表次數C = [(D-1500)/200]
mg3=>operation: M0 = 85+5*(C+1)
mg4=>operation: C無條件進位
mg5=>operation: 跳表車資M0
mg6=>operation: M1 = 20
mg7=>operation: M1 = 0
mg8=>operation: 里程數D(公尺)
io0=>inputoutput: 夜間加成M1
ot0=>inputoutput: 總車資M = M0+M1(元)
cond0=>condition: D >= 1500?
cond1=>condition: C為整數
cond2=>condition: 在23點-6點期間上車

st->io0->cond2

cond2(yes)->mg6->mg8
cond2(no)->mg7->mg8

mg8->mg5->cond0

cond0(yes)->mg2->cond1
cond0(no)->mg0->ot0
cond1(yes)->mg3->ot0
cond1(no)->mg4->mg1->ot0

ot0->ed

## 傅里德曼方程式
$$
H^2 = \Big({\dot{a}\over a}\Big)^2 = {8\pi G\over 3}\rho - {kc^2\over a^2} +{\Lambda c^2\over 3}
$$

$$
\sum_{i=1}^{100} i = 1+2+3+...+99+100 = 5050
$$