# 13975 - Frieren and her Rizz 2
https://acm.cs.nthu.edu.tw/problem/13975/

This question is modification of :
* 13577 - Anya loves to encrypt : https://hackmd.io/DIrF2d6tTiqpGzRowrXN-g
* 13970 - Frieren and her Rizz : https://hackmd.io/@skivap/ryeHXMkgp

If you understand the 2 questions above, this should be easy
If you don't, **I suggest you to take a look at this 2 questions first**

## Solution

1. Convert the binary into number, let say it store to variable X
2. Convert the number to character by adding 64 (see ASCII)
3. Reverse the alphabet (formula : Char = 155 - X)
4. Convert it to lowercase if the signed bit is 1 (Char = Char + 32 * signed_bit)

## First Way of Code

#include <stdio.h>

int main(){
    int binary;
    scanf("%d", &binary);
    
    int num = 0; // we will convert the binary to integer

    num += binary%10 * 1; // taking the 1st lastest digit and convert to integer
    binary = binary/10; // remove the 1st lastest digit

    num += binary%10 * 2; // taking the 2nd lastest digit and convert to integer
    binary = binary/10; // remove the 2nd lastest digit

    num += binary%10 * 4; // and so on... 
    binary = binary/10;

    num += binary%10 * 8;
    binary = binary/10;

    num += binary%10 * 16; // taking the first digit of binary
    binary = binary/10; // now the binary would be either 1 or 0 in this state

    char ch = 155 - (num + 64); // convert integer to character
    ch = ch + binary * 32; // if the signed binary is 1, it will convert to uppercase

    printf("%c\n", ch);
}

// by Aurick

## Second Way of Code

#include <stdio.h>

int main(){
    int a,b,c,d,e,f;
    scanf("%1d%1d%1d%1d%1d%1d", &a, &b, &c, &d, &e, &f);
    char ch = b * 16 + c * 8 + d * 4 + e * 2 + f + 64;
	ch = 155 - ch;
	ch = ch + a * 32;
    printf("%c\n", ch);
}

// by Aurick