# Questions for today

**Please put your questions in the chat!!**

## Completed

* nesting part 2 from practice exam --> try using this: https://www.scaler.com/topics/find-function-in-python/
* Staying on the same page --> check your e-mail (is it the "record added successfully"? I did that after 9:30am. it should be there by now. Also availabel here: http://www.cse.unsw.edu.au/~cs1010/22T2/content/lectures/form-submission-confirmation.zip)
* Upload files from last Thursday <-- Those should be updated now.
* Why the big deal about tabs vs spaces? They look the same. --> Answer: They look the same on *your* computer, but not when they change to someone else's computer.
* Are there likely to be 4 questions in the coding section? Or less? --> Answer: Unlikely. Probably only one or two.
* regarding alternative data structure for qu 4 it was hard to visualise within 3 hours. Like current we are using list of dictionaries? could it be tuple as alternative or set not sure and did not have much practice also on that. --> Answer: To get more practice on this, come up with practice questions for yourself. (You can share on the forum too.)

### Practicing Data Structures Questions

* Example questions:
* Best kind: Directly related to a computer program.
* Less good, but a great start: Any task you do, or someone does, on a daily/weekly/monthly basis.
* A start: Any hobby, activity, anything really.
* Knitting:
* Knitting patterns - collect knitting patterns
* Collect knitting patterns, each pattern includes how hard it is, maybe a list of stitches that are required to be familiar with to complete it, needle size(s), approximate time it takes to complete the project, NTH/SG user logins, liking patterns, recommending patterns, sharing photos of completed projects.
* Stitch tracker
* Enter the pattern you're working on, and tick of the stitches as you complete them.
* Fantasy sport
* Keep track of previous games data.

#### Knitting Patterns Example

**Specification**
Each knitting pattern includes:
* name/description
* category (toy, blanket, clothing...)
* How hard it is: Easy, Medium, Hard
* List of stitches required
* Needle size(s)
* Approximate time to completion

**Approach 1:**

patterns = [
{'name':'blue blanket',
 'category':'blanket',
 'ease':'easy',
 'stitches':['Garter Stitch','Stockinette Stitch'],
 'needle sizes':[4,5],
 'time':'5 hours',
 'pattern':[stitch1, stitch2, stitch3 ...]},
{'name':'red blanket',
 'category':'blanket',
 'ease':'easy',
 'stitches':['Garter Stitch','Stockinette Stitch'],
 'needle sizes':[4,5],
 'time':'5 hours',
 'pattern':[stitch1, stitch2, stitch3 ...]},}
]

Thinking about use cases - in what situation would we need this?

**Approach 2:**

patterns = {
'easy':[
    {'name':'blue blanket',
     'category':'blanket',
     'stitches':['Garter Stitch','Stockinette Stitch'],
     'needle sizes':[4,5],
     'time':'5 hours',
     'pattern':[stitch1, stitch2, stitch3 ...]},
    {'name':'red blanket',
     'category':'blanket',
     'stitches':['Garter Stitch','Stockinette Stitch'],
     'needle sizes':[4,5],
     'time':'5 hours',
     'pattern':[stitch1, stitch2, stitch3 ...]}
     ],
'medium':[],
'hard':[]
}

**Follow up question, using the data structure:**
1. Use case: The user has selected a pattern and stored its (unique) name. Given the name of a pattern, print out the pattern (sequence of stitches).
2. Use case: The user wants to knit something, but doesn't want to have to learn any new stitches. Given a list of stitches (the ones they already know), return a list of the names of all the patterns which require only those stitches.

Code to write:
* Question 1 with Approach 1
* Question 1 with Approach 2
* Question 2 with Approach 1
* Question 2 with Approach 2

Question 2 Approach 2

def get_patterns(patterns, known_stitches):
    # For each pattern
    for ease in patterns:
        for pattern in patterns['ease']
        # For each stitch in that pattern
        for stitch in 
            # Check it's in the list of known_stitches
        # If all the stitches for that pattern were known, add it to our list to return
        

Code demonstrating printing out each part of your data structure (copy straight into vscode and run):

def find_patterns(patterns, known_stitches):
    for ease in patterns:
        print(ease)
        for thing in patterns[ease]:
            print(f'   {thing}')
            for stitch in thing['stitches']:
                print(f'      {stitch}')


if __name__ == "__main__":
    patterns = [
            {'name':'blue blanket',
            'category':'blanket',
            'ease':'easy',
            'stitches':['Garter Stitch','Stockinette Stitch'],
            'needle sizes':[4,5],
            'time':'5 hours',
            'pattern':['stitch1', 'stitch2', 'stitch3']},
            {'name':'red blanket',
            'category':'blanket',
            'ease':'easy',
            'stitches':['Garter Stitch','Stockinette Stitch'],
            'needle sizes':[4,5],
            'time':'5 hours',
            'pattern':['stitch1', 'stitch2', 'stitch3']}
        ]
    
    #find_patterns(patterns, ['Garter Stitch'])

    patterns2 = {
        'easy':[
            {'name':'blue blanket',
            'category':'blanket',
            'stitches':['Garter Stitch','Stockinette Stitch'],
            'needle sizes':[4,5],
            'time':'5 hours',
            'pattern':['stitch1', 'stitch2', 'stitch3']},
            {'name':'red blanket',
            'category':'blanket',
            'stitches':['Garter Stitch','Stockinette Stitch'],
            'needle sizes':[4,5],
            'time':'5 hours',
            'pattern':['stitch1', 'stitch2', 'stitch3']}
            ],
        'medium':[],
        'hard':[]
        }
    find_patterns(patterns2, ['Garter Stitch'])