## 題解 ```python=! # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def addTwoNumbers(self, l1: Optional[ListNode], l2: Optional[ListNode]) -> Optional[ListNode]: output = ListNode() cur = output pre = 0 while l1 or l2 or pre: # 如果 l1 or l2 都跑完 要檢查是否需要進位 sum = 0 + pre if l1: sum += l1.val l1 = l1.next if l2: sum += l2.val l2 = l2.next cv = sum % 10 pre = sum // 10 cur.next = ListNode(cv) cur = cur.next return output.next ```