# [1365. How Many Numbers Are Smaller Than the Current Number](https://leetcode.com/problems/how-many-numbers-are-smaller-than-the-current-number/)

int* smallerNumbersThanCurrent(int* nums, int numsSize, int* returnSize){

*returnSize=numsSize;
int* returnN = malloc(sizeof(int) * numsSize);
for(int i=0;i<numsSize;i++)
{
int n=0;
for(int j=0;j<numsSize;j++)
{
if(nums[j]<nums[i])
{
n++;
}
}
returnN[i]=n;
}
return returnN;
}