# [1678. Goal Parser Interpretation](https://leetcode.com/problems/goal-parser-interpretation/)

char * interpret(char * command){
int n=0;
for(int i=0;i<strlen(command);i++)
{
if(command[i]=='G')
{
command[n]='G';
}
else if(command[i]=='('&&command[i+1]==')')
{
command[n]='o';
i++;
}
else if(command[i]=='('&&command[i+1]=='a')
{
command[n]='a';
command[n+1]='l';
i=i+3;
n++;
}
n++;
}
command[n]='\0';
return command;
}