# Leetcode #7 Reverse Integer
## 題目
Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

## [Think]

只要用一個變數去記錄新的數字就好了。
如果大於`INT_MAX`，直接 `return 0`

class Solution {
public:
    int reverse(int x) {
        int res = 0;
        while (x != 0) {
            if (abs(res) > INT_MAX / 10) return 0;
            res = res * 10 + x % 10;
            x /= 10;
        }
        return res;
    }
};

###### tags: `Leetcode` `Easy`