基本課題
```
整数の配列が与えられます。配列から2つの異なる要素の和を取り、指定された数を作れるかどうかを教えてください。
You are given an array of integers and a number.
Please return true if there is any pair of integers that sums to the number
Examples:
[1, 2, 3], 3 => True (1 + 2 = 3)
[1, 1, 1], 2 => True (1 + 1 = 2)
[1, 1, 1], 3 => False
[1], 2 => False
[1, 1], 2 => True
[1, 3], 2 => False
```
```javascript=
/**
* @param numbers Array<number> 配列
* @param target number 目標の数字
*/
function sumExists(numbers, target) {
let items = {}
for (let i = 0; i < numbers.length; i++) {
items[numbers[i]] = i;
}
console.log(items)
for (let i = 0; i < numbers.length; i++) {
if (!!items[target - numbers[i]] && items[target - numbers[i]] != i ) {
console.log(items[target - numbers[i]])
return true;
}
}
return false;
}
function sumExists(numbers, target) {
let items = {};
for (let i = 0; i < numbers.length; i++) {
if (items[target - numbers[i]]) return true;
items[numbers[i]] = true;
}
return false;
}
```
応用課題
Extension Problem
```
整数の配列が与えられます。配列から任意の数の要素の和を取り、指定された数を作れるかどうかを教えてください
You are given an array of integers (numbers) and an integer (target)
Please return true if there is any combination of elements in numbers that sums to target.
例:
[1, 1, 1], 1 => True (1 = 1)
[1, 1, 1], 2 => True (1 + 1 = 2)
[1, 1, 1], 3 => True (1 + 1 + 1 = 3)
[1, 1, 1], 4 => False
```
```ruby
```