# 13552 - Easy math problems
>author: Utin
###### tags: `math`

---

## Brief
See the code below

## Solution 0

#include <stdio.h>

int main() {
    float x, y;
    char c;
    scanf("%f %c %f", &x, &c, &y);
    if (c == '/') printf("%.3f\n", x / y);
    else if (c == '*') printf("%.3f\n", x * y);
    else if (c == '+') printf("%.3f\n", x + y);
    else if (c == '-') printf("%.3f\n", x - y);
}

// By Utin

## Reference