--- link: https://leetcode.com/problems/lowest-common-ancestor-of-a-binary-tree/ tags: tree, bt --- # 236. Lowest Common Ancestor of a Binary Tree ## Question Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree. According to the [definition of LCA on Wikipedia](https://en.wikipedia.org/wiki/Lowest_common_ancestor): “The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (where we allow **a node to be a descendant of itself**).” Given the following binary tree: root = [3,5,1,6,2,0,8,null,null,7,4] ![img](https://assets.leetcode.com/uploads/2018/12/14/binarytree.png) **Example 1:** ``` Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 1 Output: 3 Explanation: The LCA of nodes 5 and 1 is 3. ``` **Example 2:** ``` Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 4 Output: 5 Explanation: The LCA of nodes 5 and 4 is 5, since a node can be a descendant of itself according to the LCA definition. ``` **Note:** - All of the nodes' values will be unique. - p and q are different and both values will exist in the binary tree. ## Solution: Python ```python= # Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution(object): def lowestCommonAncestor(self, root, p, q): """ :type root: TreeNode :type p: TreeNode :type q: TreeNode :rtype: TreeNode """ self.lca = None self.helper(root, p, q) return self.lca def helper(self, node, p, q): if node is None: return False, False l_found_p, l_found_q = self.helper(node.left, p, q) r_found_p, r_found_q = self.helper(node.right, p, q) n_found_p, n_found_q = node == p, node == q found_p = (l_found_p or r_found_p or n_found_p) found_q = (l_found_q or r_found_q or n_found_q) if found_p and found_q: self.lca = node return False, False return found_p, found_q ``` ## Solution: Java ```java= ```