1536=512*3
# dzielnikow 60 = ?
n = p1^a1*p2^a2*...*pk^ak
(a1+1)*(a2+1)*...*(ak+1)

m|n => n = m*c
m = p1^b1*p2^b2*...*pk^bk,
bi <= ai

10^18 < 2^n 10^18 = 1000^6 < 1024^6 = (2^10)^6 = 2^60

[0, 100] -> [0, 50] -> [0, 40] -> [0, 32] ->
[11, 32] -> [20, 32] -> [20, 25] -> [22, 25] -> [24, 25] 

3 < log_3(75) < 4

2 ~~4 6 8 10 12..~~
3 ~~6 9 12..~~
5 ~~10 15 20...~~
7 ~~14 21 28..~~
11 ~~22 33~~

f(1) = 1
f(2k) = f(k) + 1
f(3k) = f(k) + k
f(k) = f(k-1)+2

f(420)=?
f(420) -> f(210)+1 -> f(105)+1 -> f(35)+35
-> f(34)+2 -> f(17)+1 -> f(16)+2 -> f(8)+1 ->
f(4)+1 -> f(2)+1 -> f(1) + 1 -> 1

int f(int k){
    if(k==1) return 1;
    if(k%2==0) return f(k/2) + 1;
    if(k%3==0) return f(k/3) + k/3;
    return f(k-1) + 2;
}

**Marcel Kubara
Bruno Kożuch
Adrian Mikoda
Dominika Mendyk
Ksawery Krajewski
Bartosz Małecki
_printf("%s",imie"); //printuje stringa imie_ Jakub Nowak
Myroslava Filinska
Vlad Nikonenko
Piotr Kowalski
Jędrek Kwiecień
**