---
###### tags: `Leetcode`
---
# Leetcode 1967. Number of Strings That Appear as Substrings in Word

[link](https://leetcode.com/problems/number-of-strings-that-appear-as-substrings-in-word/description/)

---

Given an array of strings patterns and a string word, return the number of strings in patterns that exist as a substring in word.

A substring is a contiguous sequence of characters within a string.

#### Example 1:

Input: patterns = ["a","abc","bc","d"], word = "abc"
Output: 3
Explanation:
- "a" appears as a substring in "abc".
- "abc" appears as a substring in "abc".
- "bc" appears as a substring in "abc".
- "d" does not appear as a substring in "abc".
3 of the strings in patterns appear as a substring in word.

#### Example 2:

Input: patterns = ["a","b","c"], word = "aaaaabbbbb"
Output: 2
Explanation:
- "a" appears as a substring in "aaaaabbbbb".
- "b" appears as a substring in "aaaaabbbbb".
- "c" does not appear as a substring in "aaaaabbbbb".
2 of the strings in patterns appear as a substring in word.

#### Example 3:

Input: patterns = ["a","a","a"], word = "ab"
Output: 3
Explanation: Each of the patterns appears as a substring in word "ab".

#### Constraints:

- 1 <= patterns.length <= 100
- 1 <= patterns[i].length <= 100
- 1 <= word.length <= 100
- patterns[i] and word consist of lowercase English letters.

---

Iterating the given patterns, count the number of those elements that exist as a substring in the given word.

#### Solution 1

class Solution:
    def numOfStrings(self, patterns: List[str], word: str) -> int:
        count = 0
        for i in patterns:
            if i in word:
                count += 1

        return count

        

O(T): O(N)
O(S): O(1)