Math 181 Miniproject 5: Hours of Daylight.md
---
---
tags: MATH 181
---

Math 181 Miniproject 5: Hours of Daylight
===

**Overview:** This miniproject will apply what you've learned about derivatives so far, especially the Chain Rule, to analyze the change the hours of daylight.

**Prerequisites:** The computational methods of Sections 2.1--2.5 of *Active Calculus*, especially Section 2.5 (The Chain Rule).

---

:::info
The number of hours of daylight in Las Vegas on the $x$-th day of the year ($x=1$ for Jan 1) is given by the function together with a best fit curve from Desmos.}[^first]
[^first]: The model comes from some data at http://www.timeanddate.com/sun/usa/las-vegas?

\\[
D(x)=12.1-2.4\cos \left(\frac{2\pi \left(x+10\right)}{365}\right).
\\]
(1) Plot a graph of the function $D(x)$. Be sure to follow the guidelines for formatting graphs from the specifications page for miniprojects.
:::

(1)

:::info
(2) According to this model how many hours of daylight will there be on July 19 (day 200)?
:::

(2)
According to the model on July 19 there will be 14.24 hours of daylight,

:::info
(3) Go to http://www.timeanddate.com/sun/usa/las-vegas? and look up the actual number of hours of daylight for July 19 of this year. By how many minutes is the model's prediction off of the actual number of minutes of daylight?
:::

(3) The actual number of hours of daylight for July 19,2020 will be 14.17 hours. The hours of daylight predicted by the model is 4.2 minutes off.

:::info
(4) Compute $D'(x)$. Show all work.
:::

(4)
Apply the difference rule:$d/dx f(x)-g(x)=f'(x)-g'(x)$
\\[
D(x)=12.1-2.4\cos \left(\frac{2\pi \left(x+10\right)}{365}\right)
\\]

\\[
D'(x)= d/dx [12.1]- d/dx [2.4\cos \left(\frac{2\pi \left(x+10\right)}{365}\right)]
\\]

\\[
D'(x)= 0- (-2.4\sin \left(\frac{2\pi \left(x+10\right)}{365}\right)
\\]

\\[
D'(x)= 2.4\ sin \left(\frac{2\pi \left(x+10\right)}{365}\right).
\\]
Apply the chain rule: $$ d/dx [f(g(x))]=f'(g(x))*g'(x)$$
\\[
D'(x)= 2.4\ sin \left(\frac{2\pi\left(x+10\right)}{365} \right) *d/dx \left[\frac{2\pi \left(x+10\right)}{365}\right]
\\]

\\[
D'(x)= 2.4\ sin \left(\frac{2\pi \left(x+10\right)}{365} \right) * \left(\frac{2\pi \left(1+0\right)}{365}\right)
\\]

**\\[
D'(x)= 2.4\ sin \left(\frac{2\pi \left(x+10\right)}{365} \right) * \left(\frac{2\pi }{365}\right)
\\]**

:::info
(5) Find the rate at which the number of hours of daylight are changing on July 19. Give your answer in minutes/day and interpret the results.
:::
(5) The rate at which the number of hours of daylight are changing on July 19 based of D'(x) is 0.0188 minutes/day. This means that every 0.0188 minutes the amount of daylight time is decreasing

:::info
(6) Note that near the center of the year the day will reach its maximum length when the slope of $D(x)$ is zero. Find the day of the year that will be longest by setting $D'(x)=0$ and solving.
:::

(6)
\\[
0= 2.4\ sin \left(\frac{2\pi \left(x+10\right)}{365} \right) * \left(\frac{2\pi }{365}\right).
\\]

\\[(365)0= 2.4\ sin \left(\frac{2\pi \left(x+10\right)}{365} \right) * \left(\frac{2\pi }{365}\right)* (365).
\\]

\\[0= 2.4\ sin \left(\frac{2\pi \left(x+10\right)}{365} \right) *6.283185307
\\]

\\[0= 15.07964474\ sin \left(\frac{2\pi \left(x+10\right)}{365} \right)
\\]

\\[0/15.07964474= \left(\frac{15.07964474\ sin }{15.07964474} \right) \left(\frac{2\pi \left(x+10\right)}{365} \right)
\\]

\\[0= sin \left(\frac{2\pi \left(x+10\right)}{365} \right)
\\]

\\[\pi+ 2\pi k= sin \left(\frac{2\pi \left(x+10\right)}{365} \right)
\\]

$$...$$
\\[x= (1075/2) ,x=537.5
\\]
$$537.6-365=172.5$$
The 172.5th day of the year is the day that will be longest with D(172.5)= 14.5 hours of daylight

:::info

(7) Write an explanation of how you could find the day of the year when the number of hours of daylight is increasing most rapidly.
:::

(7) To find the day of the year when the number of hours of daylight is increasing most rapidy is by using D'(x) and inputting a range above negative or zero for x where x>0

---

To submit this assignment click on the Publish button . Then copy the url of the final document and submit it in Canvas.