--- title: Stat03 tags: Stat --- ![](https://i.imgur.com/zJPrIF8.jpg) ![](https://i.imgur.com/6Q689pj.jpg) ![](https://i.imgur.com/uBluFcR.jpg) ![](https://i.imgur.com/rGlTJcC.jpg) --- ### Original definition of the probability of a simple event #### Example of tossing a coin. We would like to know the probability of getting a head. Simple events: $H$: a head, $T$: tail, Sample space: $S=\{H, T\}$ In reality, suppose we toss the coin 10 times, we observe $HHHTTTHTHH$. 1. The *relative frequency* (相對頻率,比例) of observing a head is $$\frac{f}{n}=\frac{6}{10}=60\%.$$ 2. The *probability* of observing a head is $$P(H)=\lim_{n\rightarrow \infty}\frac{f}{n}.$$ :::success Human beings start to explore the idea of limit in calculus. ::: ### Examples of interpreting a probability --- #### Example 1. Suppose a fair coin is tossed. The *probability of getting a head* is 50\%. Interpretations: In *repeated sampling* (tossing a coin for infinitely times), a head is obtained for *about* 50\% of the times. --- #### Example 2. How do you interpret the probability of rain on Friday is 40\%? Interpretations: In *repeated sampling*, *about* 40\% of the days will rain. ![](https://i.imgur.com/k3VnpPU.jpg) --- #### Probability Axiom to calculate a Probability ##### Toss a Coin Suppose we toss a fair coin. Sample space, $S = \{H, T\}$. (1). $P(H)=P(T)$. (2). $P(S) = 1$. (3). $P(S) = P(H)+P(T)$ (4). $P(S) \stackrel{(3)}{=} P(H)+P(T) \stackrel{(2)}{=} 1 \stackrel{(1)}{=} 2P(H)$ (5). $P(H) = 1/2$. --- #### $P^n_r$, 排列數 An application of the $MN$ rule: \begin{eqnarray*} P^n_r &=& (n)\times (n-1)\times\cdots \times (n-r+1)\\ &=& (n)\times (n-1)\times\cdots \times (n-r+1)\times \frac{(n-r)\times (n-r-1)\times\cdots\times 1}{(n-r)\times (n-r-1)\times\cdots 1}\\ &=& \frac{n!}{(n-r)!}. \end{eqnarray*} --- #### Example. (orders matter!) A box contains six M&Ms®, four red and two green. A child selects two M&Ms at random. What is the probability that exactly one is red? Sol: Suppose order matter! Let $A$ denote the note that exactly one is red. Suppose orders of these two M&Ms matter. $$\# S = P^{6}_2 =\frac{6!}{(6-2)!}= 30.$$ The number of exactly one red M&M: $$\#A = 2\times 4 + 4\times2 = 16.$$ $$P(A)=\frac{\# A}{\# S} = \frac{16}{30}=\frac{8}{15}.$$ --- #### $C^n_r$, 組合數 \begin{eqnarray*} C^{n}_r & =& \frac{P^n_r}{r!}=\frac{ \frac{n!}{(n-r)!}}{r!}=\frac{n!}{(n-r)!r!}. \end{eqnarray*} --- #### Sets operations 1. union of $A$ and $B$: 聯集 2. intersection of $A$ and $B$: 交集 3. complement of set $A$: 捕集 --- #### $\phi$, an empty set Let $\phi=\{\}$ denote the empty set. If two events are mutually exclusive, we write $$A\cap B = \phi. $$ $$P(\phi) = 0.$$ --- #### Another definition of independence (1) $A$ and $B$ are independent if only if 1. $P(A|B) =P(A)$, 2. $P(B|A) = P(B)$. From 1, we have $$P(A|B)=\frac{P(A\cap B)}{P(B)} =P(A)=> P(A\cap B) = P(A)P(B) $$ From 2, we have $$P(B|A)=\frac{P(B\cap A)}{P(A)}=P(B) => P(B\cap A)=P(A)P(B).$$ (2) $A$ and $B$ are independent, if and only if $P(A\cap B) =P(A)P(B)$. --- :::warning Interpretations: 1. Confidence interval 2. Hypothesis test :::