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title: My lesson Topic

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Math 181 Miniproject 3: Texting Lesson.md
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My lesson Topic
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<i class="fa fa-envelope fa-2x"></i>
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<i class="fa fa-camera fa-2x"></i>
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<i class="fa fa-comments fa-2x"></i>
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<i class="fa fa-address-card fa-2x" aria-hidden="true"></i>
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<i class="fa fa-phone fa-2x" aria-hidden="true"></i>
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<i class="fa fa-list-ul fa-2x" aria-hidden="true"></i>
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<div><img class="left"/><div class="alert gray">

Can you help me out with this problem,I dont know what to do and I'm lost. 
</div></div> 


<div><div class="alert blue">

Which problem are you talking about? 

</div><img class="right"/></div> 


<div><img class="left"/><div class="alert gray">
f(x)=6x^2-8x, and find the exact formula for f'(x)


</div></div> 


<div>

<div><div class="alert blue">
Ok first we need to set it to f(x+h)-f(x)/h
6{x+h}^2=8{x+h}-{6x^2-8x}/h, then foil it

</div><img class="right"/></div> 

<div><img class="left"/><div class="alert gray">

Would it be like this, (6x^2 +12xh+6h^2)- (8x+8h)-6x^2-8x/h

</div></div> 

<div><div class="alert blue">

DONT FORGET to put lim h->0,every time, also cancel out. You should end up with =lim h->0 12xh+6h^2+8h


</div><img class="right"/></div>

<div><img class="left"/><div class="alert gray">

Okay thanks for letting me know, and I got that what next
</div></div> 

<div><div class="alert blue">

you can take out an h

</div><img class="right"/></div>


<div><img class="left"/><div class="alert gray">

like this right, =lim h->0 h(12x+6h+8)/h


</div></div> 

<div><div class="alert blue">

yeah, now you should be left with =lim h->0 12x+6h+8, now you can plug in the zero into the formula

</div><img class="right"/></div>


<div><img class="left"/><div class="alert gray">
so 12x+6(0)+8

</div></div> 

<div><div class="alert blue">
yep now what did you get?

</div><img class="right"/></div>


<div><img class="left"/><div class="alert gray">
12x+8 is what I got

</div></div> 

<div><div class="alert blue">
Ay lets go, you got it congrats



