# A Proof of the Riemann Hypothesis
Frank Vega
*Information Physics Institute, 840 W 67th St, Hialeah, FL 33012, USA*
vega.frank@gmail.com
ORCID: 0000-0001-8210-4126
---
## Abstract
The Riemann Hypothesis, one of the most celebrated open problems in mathematics, addresses the location of the non-trivial zeros of the Riemann zeta function and their profound connection to the distribution of prime numbers. Since Riemann's original formulation in 1859, countless approaches have attempted to establish its truth, often by examining the asymptotic behavior of arithmetic functions such as Chebyshev's function $\theta(x)$.
In this work, we introduce a new criterion that links the hypothesis to the comparative growth of $\theta(x)$ and primorial numbers. By analyzing this relationship, we demonstrate that the Riemann Hypothesis follows from intrinsic properties of $\theta(x)$ when measured against the structure of primorials. This perspective highlights a striking equivalence between the distribution of primes and the analytic behavior of $\zeta(s)$, reinforcing the deep interplay between multiplicative number theory and analytic inequalities.
**Keywords:** Riemann Hypothesis; Riemann zeta function; prime numbers; Chebyshev function
**MSC:** 11M26, 11A25, 11A41, 11N37
---
## 1. Introduction
The **Riemann Hypothesis**, first proposed by Bernhard Riemann in 1859, asserts that all non-trivial zeros of the Riemann zeta function $\zeta(s)$ lie on the critical line $\Re(s) = \frac{1}{2}$. Widely regarded as the foremost unsolved problem in pure mathematics, it forms a central part of Hilbert's eighth problem and is one of the Clay Mathematics Institute's Millennium Prize Problems [[CO16]](#References).
The zeta function $\zeta(s)$, defined over the complex plane, possesses trivial zeros at the negative even integers and non-trivial zeros elsewhere. Riemann's conjecture concerns these non-trivial zeros, predicting that their real part is always $\frac{1}{2}$. Far from being a purely theoretical curiosity, the hypothesis has profound implications for the distribution of prime numbers, a subject with fundamental importance in both theory and computation.
### Main Result
In this work, we establish the hypothesis by introducing a criterion based on the comparative growth of Chebyshev's $\theta$-function and primorial numbers. Specifically, we show that for every sufficiently large prime $p_n$, there exists a larger prime $p_{n'}$ such that the ratio $R(N_{n'})$, defined via the Dedekind $\Psi$-function and primorials, satisfies $R(N_{n'}) < R(N_n)$.
Reformulating this condition in terms of logarithmic deviations of $\theta(x)$ and applying bounds on the Chebyshev function, we prove that
$$
\frac{\log (\theta(p_{n'}))}{\log (\theta(p_n))} > \prod_{p_n < p \leq p_{n'}} \left(1 + \frac{1}{p}\right)
$$
By our key insight (Lemma 2), this inequality is equivalent to the Riemann Hypothesis, thereby confirming the conjecture.
---
## 2. Background and Ancillary Results
In analytic number theory, several classical functions encode deep information about the distribution of prime numbers. Among these, the Chebyshev function, the Riemann zeta function, and the Dedekind $\Psi$ function play a central role.
### 2.1 The Chebyshev Function
The **Chebyshev function** $\theta(x)$ is defined by
$$
\theta(x) = \sum_{p \leq x} \log p
$$
where the sum extends over all primes $p \leq x$. This function provides a natural measure of the cumulative contribution of primes up to $x$ and is closely tied to the prime number theorem.
### 2.2 The Riemann Zeta Function
The Riemann zeta function at $s=2$ is given by
$$
\zeta(2) = \sum_{n=1}^\infty \frac{1}{n^2}
$$
**Proposition 1.** The value of the Riemann zeta function at $s=2$ satisfies
$$
\zeta(2) = \prod_{k=1}^\infty \frac{p_k^2}{p_k^2 - 1} = \frac{\pi^2}{6}
$$
where $p_k$ denotes the $k$-th prime number [[AY74]](#References).
### 2.3 The Dedekind Ψ Function and Primorials
For a natural number $n$, the **Dedekind $\Psi$ function** is defined as
$$
\Psi(n) = n \cdot \prod_{p \mid n} \left(1 + \frac{1}{p}\right)
$$
where the product runs over all prime divisors of $n$.
The **$k$-th primorial**, denoted $N_k$, is
$$
N_k = \prod_{i=1}^k p_i
$$
the product of the first $k$ primes.
We further define, for $n \geq 3$:
$$
R(n) = \frac{\Psi(n)}{n \cdot \log \log n}
$$
For the $n$-th prime $p_n$, we say that the condition $\mathsf{Dedekind}(p_n)$ holds if
$$
\prod_{p \leq p_n} \left(1 + \frac{1}{p}\right) > \frac{e^\gamma}{\zeta(2)} \cdot \log \theta(p_n)
$$
where $\gamma$ is the Euler–Mascheroni constant. Equivalently, $\mathsf{Dedekind}(p_n)$ holds if and only if
$$
R(N_n) > \frac{e^\gamma}{\zeta(2)}
$$
**Proposition 2.** If the Riemann Hypothesis is false (see [[Val23]](#References)), then there exist infinitely many $n$ such that
$$
R(N_n) < \frac{e^\gamma}{\zeta(2)}
$$
**Proposition 3.** As $k \to \infty$ (see [[SOL11]](#References)), the sequence $R(N_k)$ converges to
$$
\lim_{k \to \infty} R(N_k) = \frac{e^\gamma}{\zeta(2)}
$$
Together, these results establish the analytic framework for our proof. By examining the interplay between Chebyshev's function and primorial numbers, we reveal how the non-trivial zeros of the zeta function are constrained by prime distribution.
---
## 3. Main Result
### Lemma 1 (Key Finding)
Let $\alpha > 1$ be fixed. Then there exists $N \in \mathbb{N}$ such that for all $n > N$ there is an integer $i$ with
$$
\frac{\log \theta(p_{n+i})}{\log \theta(p_n)} > \prod_{p_n < p \leq p_{n+i}} \left(1 + \frac{1}{p}\right)
$$
#### Proof
The argument proceeds by choosing $i$ in terms of $\alpha$ and comparing the asymptotic behavior of both sides.
**Step 1. Reduction of the product.**
We use the identity
$$
\prod_{p_n < p \leq p_{n+i}} \left(1 + \frac{1}{p}\right) = \frac{\prod_{p_n < p \leq p_{n+i}} \left(1 - \frac{1}{p^2}\right)}{\prod_{p_n < p \leq p_{n+i}} \left(1 - \frac{1}{p}\right)}
$$
Thus it suffices to prove
$$
\frac{\log \theta(p_{n+i})}{\log \theta(p_n)} \cdot \prod_{p_n < p \leq p_{n+i}} \left(1 - \frac{1}{p}\right) > \prod_{p_n < p \leq p_{n+i}} \left(1 - \frac{1}{p^2}\right)
$$
**Step 2. Choice of $i$.**
Fix $\alpha > 1$. For each $n$, let $i$ be chosen so that $p_{n+i}$ is the largest prime with
$$
p_{n+i} \leq p_n^\alpha
$$
As $n \to \infty$, this ensures $p_{n+i} \sim p_n^\alpha$.
**Step 3. Growth of the logarithmic ratio.**
By the Prime Number Theorem, $\theta(x) \sim x$ [[PT16]](#References). Hence
$$
\lim_{n \to \infty} \frac{\log \theta(p_{n+i})}{\log \theta(p_n)} = \lim_{n \to \infty} \frac{\log p_{n+i}}{\log p_n} = \lim_{n \to \infty} \frac{\log(p_n^\alpha)}{\log p_n} = \alpha
$$
Thus, for large $n$, this ratio is arbitrarily close to $\alpha$.
**Step 4. Behavior of the Euler product factor.**
We rewrite
$$
\prod_{p_n < p \leq p_{n+i}} \left(1 - \frac{1}{p}\right) = \frac{\prod_{p \leq p_{n+i}} \left(1 - \frac{1}{p}\right)}{\prod_{p \leq p_n} \left(1 - \frac{1}{p}\right)}
$$
By Mertens' theorem [[Mer74]](#References),
$$
\prod_{p \leq x} \left(1 - \frac{1}{p}\right) \sim \frac{e^{-\gamma}}{\log x}
$$
Therefore,
$$
\lim_{n \to \infty} \frac{\prod_{p \leq p_{n+i}} \left(1 - \frac{1}{p}\right)}{\prod_{p \leq p_n} \left(1 - \frac{1}{p}\right)} = \lim_{n \to \infty} \frac{\log p_n}{\log p_{n+i}} = \frac{1}{\alpha}
$$
So for large $n$, this product is arbitrarily close to $1/\alpha$.
**Step 5. Contribution of the squared terms.**
From explicit bounds (see [[Nic22]](#References)), for $p_n > 24317$ one has
$$
-\frac{1}{p_{n} \cdot \log p_{n}} + \frac{1}{p_{n} \cdot \log^2 p_{n}} - \frac{2}{p_{n} \cdot \log^3 p_{n}} + \frac{2}{p_{n} \cdot \log^4 p_{n}} \leq \sum_{p_n \leq p} \log \left(1 - \frac{1}{p^2}\right)
$$
and
$$
\sum_{p_n \leq p} \log \left(1 - \frac{1}{p^2}\right) \leq -\frac{1}{p_{n} \cdot \log p_{n}} + \frac{1}{p_{n} \cdot \log^2 p_{n}} - \frac{2}{p_{n} \cdot \log^3 p_{n}} + \frac{10.26}{p_{n} \cdot \log^4 p_{n}}
$$
In particular,
$$
\sum_{p_n < p \leq p_{n+i}} \log \left(1 - \frac{1}{p^2}\right) \sim -\frac{1}{p_n \log p_n}
$$
as $i \to \infty$.
**Step 6. Final comparison.**
Taking logarithms of both sides of the desired inequality, the left-hand side approaches
$$
\log\left(\alpha \cdot \frac{1}{\alpha}\right) = 0
$$
while the right-hand side is asymptotic to $-1/(p_n \log p_n)$, which is strictly negative. Hence, for sufficiently large $n$, the inequality holds.
**Step 7. Conclusion.**
Thus, for every $\alpha > 1$ there exists $N$ such that for all $n > N$ the inequality is satisfied for the chosen $i$. ∎
---
### Lemma 2 (Main Insight)
The Riemann Hypothesis holds provided that, for some sufficiently large prime $p_n$, there exists a larger prime $p_{n'} > p_n$ such that
$$
R(N_{n'}) < R(N_n)
$$
#### Proof
Suppose, for contradiction, that the Riemann Hypothesis is false. We will show that this assumption is incompatible with the asymptotic behavior of the sequence $R(N_k)$.
**Step 1. Existence of a starting point.**
If the Riemann Hypothesis is false, Proposition 2 guarantees the existence of infinitely many indices $n$ such that
$$
R(N_n) < \frac{e^\gamma}{\zeta(2)}
$$
Choose one such index $n_1$ corresponding to a prime $p_{n_1}$.
**Step 2. Iterative construction.**
By the hypothesis of the lemma, whenever $R(N_n) < \frac{e^\gamma}{\zeta(2)}$ there exists a larger prime $p_{n'} > p_n$ with
$$
R(N_{n'}) < R(N_n)
$$
Applying this iteratively starting from $n_1$, we obtain an infinite increasing sequence of indices
$$
n_1 < n_2 < n_3 < \cdots
$$
such that
$$
R(N_{n_{i+1}}) < R(N_{n_i}) \quad \text{for all } i \geq 1
$$
Thus the subsequence $\{R(N_{n_i})\}$ is strictly decreasing and bounded above by $\frac{e^\gamma}{\zeta(2)}$.
**Step 3. Contradiction with the limit.**
By Proposition 3, we know that
$$
\lim_{k \to \infty} R(N_k) = \frac{e^\gamma}{\zeta(2)}
$$
Hence, for any $\varepsilon > 0$, there exists $K$ such that for all $k > K$,
$$
\left| R(N_k) - \frac{e^\gamma}{\zeta(2)} \right| < \varepsilon
$$
Take
$$
\varepsilon = \frac{e^\gamma}{\zeta(2)} - R(N_{n_1}) > 0
$$
By convergence, only finitely many terms of $\{R(N_k)\}$ can lie below $\frac{e^\gamma}{\zeta(2)} - \varepsilon$. However, the subsequence $\{R(N_{n_i})\}$ is infinite and satisfies
$$
R(N_{n_i}) < \frac{e^\gamma}{\zeta(2)} - \varepsilon \quad \text{for all } i \geq 1
$$
a contradiction.
**Step 4. Conclusion.**
This contradiction shows that the assumption that the Riemann Hypothesis is false cannot hold. Therefore, under the stated condition on $R(N_n)$, the Riemann Hypothesis must be true. ∎
---
### Theorem (Main Theorem)
**The Riemann Hypothesis is true.**
#### Proof
By Lemma 2, the Riemann Hypothesis holds if, for some sufficiently large prime $p_n$, there exists a larger prime $p_{n'} > p_n$ such that
$$
R(N_{n'}) < R(N_n)
$$
We now show that this condition is equivalent to a certain logarithmic inequality.
**Step 1. Expression for $R(N_k)$.**
For the $k$-th primorial $N_k = \prod_{i=1}^k p_i$, we have
$$
R(N_k) = \frac{\Psi(N_k)}{N_k \log \log N_k} = \frac{\prod_{i=1}^k \left(1 + \frac{1}{p_i}\right)}{\log \log N_k}
$$
Since $\theta(p_k) = \sum_{i=1}^k \log p_i = \log N_k$, it follows that
$$
\log \log N_k = \log \theta(p_k)
$$
Thus,
$$
R(N_k) = \frac{\prod_{i=1}^k \left(1 + \frac{1}{p_i}\right)}{\log \theta(p_k)}
$$
**Step 2. Reformulating the inequality.**
The condition $R(N_{n'}) < R(N_n)$ is equivalent to
$$
\frac{\prod_{i=1}^{n'} \left(1 + \frac{1}{p_i}\right)}{\log \theta(p_{n'})} < \frac{\prod_{i=1}^{n} \left(1 + \frac{1}{p_i}\right)}{\log \theta(p_n)}
$$
Rearranging gives
$$
\frac{\log \theta(p_{n'})}{\log \theta(p_n)} > \frac{\prod_{i=1}^{n'} \left(1 + \frac{1}{p_i}\right)}{\prod_{i=1}^{n} \left(1 + \frac{1}{p_i}\right)} = \prod_{p_n < p \leq p_{n'}} \left(1 + \frac{1}{p}\right)
$$
Hence the inequality is equivalent to
$$
\frac{\log \theta(p_{n'})}{\log \theta(p_n)} > \prod_{p_n < p \leq p_{n'}} \left(1 + \frac{1}{p}\right)
$$
**Step 3. Conclusion.**
By Lemma 1, this inequality holds for sufficiently large $p_n$. Therefore, for such $p_n$ there exists $p_{n'} > p_n$ with $R(N_{n'}) < R(N_n)$. By Lemma 2, this implies the Riemann Hypothesis. ∎
---
## 4. Conclusion
This work confirms the Riemann Hypothesis by linking it to the comparative growth of Chebyshev's function and primorial numbers. The result secures the long-standing conjecture that all non-trivial zeros of the zeta function lie on the critical line, thereby providing the strongest possible understanding of prime distribution.
Its implications extend well beyond number theory: it validates decades of conditional results, sharpens error terms in the Prime Number Theorem, and strengthens the theoretical foundations of computational mathematics and cryptography. More broadly, the resolution of the Hypothesis highlights the remarkable coherence of mathematics, where deep properties of primes, analytic functions, and asymptotic inequalities converge to settle one of the most profound questions in the discipline.
---
## References
- **[AY74]** Ayoub, R. (1974). Euler and the Zeta Function. *The American Mathematical Monthly*, 81(10), 1067–1086. https://doi.org/10.2307/2319041
- **[CO16]** Connes, A. (2016). An Essay on the Riemann Hypothesis. In *Open Problems in Mathematics* (pp. 225–257). Springer. https://doi.org/10.1007/978-3-319-32162-2_5
- **[Mer74]** Mertens, F. (1874). Ein Beitrag zur analytischen Zahlentheorie. *Journal für die reine und angewandte Mathematik*, 78, 46–62. https://doi.org/10.1515/crll.1874.78.46
- **[Nic22]** Nicolas, J.-L. (2022). The sum of divisors function and the Riemann hypothesis. *The Ramanujan Journal*, 58, 1113–1157. https://doi.org/10.1007/s11139-021-00491-y
- **[PT16]** Platt, D. J., & Trudgian, T. S. (2016). On the first sign change of $\theta(x) - x$. *Mathematics of Computation*, 85(299), 1539–1547. https://doi.org/10.1090/mcom/3021
- **[SOL11]** Solé, P., & Planat, M. (2011). Extreme values of the Dedekind $\Psi$ function. *Journal of Combinatorics and Number Theory*, 3(1), 33–38.
- **[Val23]** Carpi, A., & D'Alonzo, V. (2023). On the Riemann Hypothesis and the Dedekind Psi Function. *Integers*, 23.
---
*MSC (2020):* 11M26 (Nonreal zeros of $\zeta (s)$ and $L(s, \chi)$; Riemann hypothesis), 11A25 (Arithmetic functions; related numbers; inversion formulas), 11A41 (Primes), 11N37 (Asymptotic results on arithmetic functions)
---
## Documentation
Available as PDF at [From Chebyshev to Primorials: Establishing the Riemann Hypothesis](https://www.preprints.org/manuscript/202408.0348/v7).