## 1. Exclusivity: Frontier Cluster
> Welcome back, Space Cowboy. The Minutemen have intercepted a cryptic signal from the Frontier Board—a corrupted data stream filled with duplicate entries. Hidden within this mess are critical coordinates that could lead us closer to the legendary Starry Spur.
>
>Your mission is to sift through this chaotic stream and extract the unique entries. These coordinates must be preserved in the order they were received to maintain their integrity. Any duplicates are remnants of the Board's sabotage—eliminate them swiftly.
>
>Once you've completed the task, report the refined list to Lena Starling. Time is of the essence, Cowboy—the resistance is counting on you!

> Example
Input
String Input: 7 3 7 9 1 3 5 9
Output
String Expected Output: 7 3 9 1 5

# take in the number
n = input()

# calculate answer
def remove_duplicates(input_string):
    unique_numbers = []
    seen = set()
    for num in input_string.split():
        if num not in seen:
            unique_numbers.append(num)
            seen.add(num)
    return ' '.join(unique_numbers)

# process the input to calculate the answer
result = remove_duplicates(n)

# print answer
print(result)

23 28 13 100 34 50 89 14 91 42 13 14 70 82 7 21 15 35 15 83 97 66 88 58 17 63 83 13 62 75 7 46 67 66 54 20 19 46 64 40 51 97 95 50 58 72 87 85 41 92 39 62 78 81 9 100 25 32 90 44 56 18 80 56 29 50 81 93 91 76 81 24 18 18 71 66 2 52 24 7 27 41 95 94 33 86 71 57 24 6 24 2 31 68 7 34 82 32 91 70 27 17 36 62 33 55 60 37 55 98 70 78 7 96 24 54 67 70 94 87 34 6 73 70 11 80 40 79 78 2 55 53 79 81 4 76 90 47 67 25 9 37 99 47 67 55 33 41 25 23 32 34 65 72 84 15 51 98 53 84 70 15 73 33 60 9 90 64 66 40 64 2 74 13 86 3 41 100 11 36 7 38 77 85 46 9 2 17 78 17 97 26 91 49 83 16 23 41 27 98
Output:
23 28 13 100 34 50 89 14 91 42 70 82 7 21 15 35 83 97 66 88 58 17 63 62 75 46 67 54 20 19 64 40 51 95 72 87 85 41 92 39 78 81 9 25 32 90 44 56 18 80 29 93 76 24 71 2 52 27 94 33 86 57 6 31 68 36 55 60 37 98 96 73 11 79 53 4 47 99 65 84 74 3 38 77 26 49 16

---
## 2. Weighted Starfield Stabilizer
Weighted Starfield Stabilizer
Welcome, Space Cowboy. The resistance has intercepted energy signals from the Frontier Starfield, but they are riddled with weighted anomalies that distort their stability. To analyze the starfield’s stability, you must calculate the maximum stability score.

Each energy signal is modified by its corresponding weight, creating a new stability signal:
Modified Signal = Signal × Weight

Your mission is to identify the maximum stability score for any contiguous subarray of the modified signals. Use your computational skills to ensure the accuracy of your findings!

Answer Format:
Return a single integer representing the maximum stability score from the starfield.

Report your findings to Lena Starling. The resistance depends on your precision to restore balance in the starfield!

Example
Input
Input:
signals = [1, -2, 3, -4]
weights = [2, 3, -1, 4]

Output
Output:
48
Explanation:
To compute the maximum stability score, follow these steps:

Calculate the modified signals:
1 × 2 = 2
-2 × 3 = -6
3 × -1 = -3
-4 × 4 = -16
The modified signals are:
[2, -6, -3, -16]
Find the maximum product of any contiguous subarray:
Subarray
[2] : Product = 2
Subarray
[-6] : Product = -6
Subarray
[2, -6] : Product = -12
Subarray
[-3, -16] : Product = 48
The maximum product is 48, which occurs for the subarray
[-3, -16]

# Function to calculate the maximum product of any contiguous subarray
def max_product_subarray(arr):
    if not arr:
        return 0

    max_product = arr[0]
    min_product = arr[0]
    result = arr[0]

    for i in range(1, len(arr)):
        if arr[i] < 0:
            max_product, min_product = min_product, max_product
        
        max_product = max(arr[i], max_product * arr[i])
        min_product = min(arr[i], min_product * arr[i])
        
        result = max(result, max_product)

    return result

# Input two arrays as strings
signals_str = input().strip()  # Example: "1,-2,3,-4"
weights_str = input().strip()  # Example: "2,3,-1,4"

# Convert the input strings to lists of integers
# Remove any unwanted characters and split by comma
signals = list(map(int, signals_str.strip('[]').split(',')))
weights = list(map(int, weights_str.strip('[]').split(',')))

# Calculate the modified signals
modified_signals = [signal * weight for signal, weight in zip(signals, weights)]

# Calculate the maximum stability score
max_stability_score = max_product_subarray(modified_signals)

# Print the maximum stability score
print(max_stability_score)

Input:
[81, -26, 18, 65, -24, 17, 79, 26, 15, -5, -70, 88, 99, 47, -90, -100, 84, 68, 47, -71] [4, 5, 9, 19, 15, 12, 12, 13, 5, 13, 15, 4, 20, 3, 16, 2, 14, 10, 19, 7]
Output:
20515358335313379932515165032960491520000000000000

---
## 3. WordWrangler
Welcome, Space Cowboy. The Frontier Archives have transmitted an ancient text encrypted with layers of forgotten languages. The resistance needs your help to decode the most frequently used word in this transmission.

Your mission is to count the frequency of each word in the given text, ignoring case and punctuation, and identify the single most common word. If there are multiple words with the same highest frequency, return any one of them.

Answer Format:
Return the most common word as a single string. Do not include its count in the output.

Report the result back to Lena Starling. The resistance is counting on your precision and speed!

Example
Input
Input:
"The quick brown fox jumps over the lazy dog. The dog barks at the fox!"

Output
Output:
the

import re
from collections import Counter

# Input the text as a single string
input_text = input()  # Example: "The quick brown fox jumps over the lazy dog."

# Normalize the text: convert to lowercase and remove punctuation
normalized_text = re.sub(r'[^\w\s]', '', input_text.lower())

# Split the text into words
words = normalized_text.split()

# Count the frequency of each word
word_counts = Counter(words)

# Find the most common word
most_common_word, _ = word_counts.most_common(1)[0]

# Print the most common word
print(most_common_word)

Input:
snypa csviwm zhfltij fnc snypa ayjnd iava ayjnd kabcu snypa iava kabcu kabcu fnc kabcu iava zhfltij kabcu iava snypa kabcu zhfltij ayjnd kabcu kabcu kabcu ayjnd kabcu zhfltij iava fbg kabcu zhfltij dssek kabcu dssek iava kabcu fhzclrf csviwm fnc fbg kabcu fbg csviwm kabcu fnc csviwm dssek ayjnd iava dssek snypa fnc csviwm kabcu csviwm kabcu csviwm fhzclrf kabcu kabcu iava fhzclrf ayjnd snypa snypa kabcu dssek kabcu kabcu ayjnd fbg fbg csviwm fbg kabcu fnc csviwm kabcu fhzclrf dssek fhzclrf iava fbg kabcu csviwm ayjnd ayjnd kabcu ayjnd zhfltij fbg kabcu ayjnd csviwm kabcu fhzclrf kabcu fhzclrf kabcu snypa fhzclrf dssek fbg kabcu kabcu zhfltij kabcu ayjnd kabcu fnc csviwm kabcu kabcu kabcu iava fhzclrf kabcu snypa kabcu kabcu fhzclrf kabcu kabcu fbg csviwm iava kabcu kabcu dssek iava kabcu zhfltij iava kabcu kabcu kabcu zhfltij zhfltij fnc zhfltij iava zhfltij fhzclrf fhzclrf kabcu iava kabcu iava
Output:
kabcu

---
## 4. Energy Matrix Activation
Greetings, Space Cowboy. The resistance has uncovered the ancient Starry Spur, but its power lies dormant. To activate the energy matrix, you must combine specific energy crystals to reach a precise energy level.

Your mission is to calculate the number of ways to combine these crystals to match the required energy level. Each crystal can be used an unlimited number of times, but the combinations must add up to the exact target energy.

Report the number of valid combinations to Lena Starling. The fate of the resistance rests in your calculations!

Example
Input
Example 1:
Energy Crystals: [1, 2, 3]
Target Energy: 4

Example 2:
Energy Crystals: [2, 5, 3, 6]
Target Energy: 10

Output
Example 1 Output: 4
Explanation: There are 4 distinct ways to combine the crystals to reach the target energy level of 4:

1 + 1 + 1 + 1
1 + 1 + 2
2 + 2
1 + 3
Example 2 Output: 5
Explanation: There are 5 distinct ways to combine the crystals to reach the target energy level of 10:

2 + 2 + 2 + 2 + 2
2 + 2 + 2 + 2 + 2 + 2 + 3
2 + 2 + 2 + 6
5 + 5
2 + 3 + 5
Each combination adds up to the target energy level of 10. As before, the order of the crystals does not matter.

# Function to calculate the number of ways to reach the target energy level
def count_combinations(crystals, target):
    # Create a list to store the number of ways to reach each energy level
    dp = [0] * (target + 1)
    dp[0] = 1  # There's one way to reach the target of 0 (using no crystals)

    # Iterate over each crystal
    for crystal in crystals:
        # Update the dp array for each energy level from crystal to target
        for energy in range(crystal, target + 1):
            dp[energy] += dp[energy - crystal]

    return dp[target]

# Input energy crystals and target energy as strings
energy_crystals_str = input().strip()  # Input as a string
target_energy_str = input().strip()  # Input as a string

# Convert the input strings to a list of integers and an integer
# Remove any unwanted characters and split by comma
energy_crystals = list(map(int, energy_crystals_str.strip('[]').split(',')))
target_energy = int(target_energy_str)

# Calculate the number of ways to reach the target energy level
number_of_ways = count_combinations(energy_crystals, target_energy)

# Print the number of ways
print(number_of_ways)

Input:
[41, 31, 36, 19, 15, 31, 17, 2] 174
Output:
1311

---
## 5. ConflictCruncher
Welcome back, Space Cowboy. The Minutemen have uncovered multiple encrypted data streams from the Frontier Board. These streams contain critical intelligence, but their keys overlap in ways that cause conflicts.

Your mission is to merge these conflicting data streams into a single dictionary. When conflicts arise (identical keys), you must apply the Frontier Protocol: retain the value from the second dictionary and discard the conflicting value from the first.

Complete this task swiftly and accurately, Cowboy, and report the unified dictionary back to Lena Starling. The fate of the resistance may depend on it!

Example
Input
String Dict input: {'a': 1, 'b': 2, 'c': 3}, {'b': 4, 'd': 5}

Output
Merged Output: {'a': 1, 'b': 4, 'c': 3, 'd': 5}

# Function to merge two dictionaries according to the Frontier Protocol
def merge_dicts(dict1, dict2):
    # Create a new dictionary to hold the merged result
    merged_dict = dict1.copy()  # Start with the first dictionary
    merged_dict.update(dict2)    # Update with the second dictionary, which will overwrite conflicts
    return merged_dict

# Input two dictionaries as strings
dict1_str = input()
dict2_str = input()

# Convert the input strings to dictionaries
dict1 = eval(dict1_str)
dict2 = eval(dict2_str)

# Merge the dictionaries
merged_output = merge_dicts(dict1, dict2)

# Print the merged output
print(merged_output)