切割網址取得不同部分
===

要先將 `string` 轉為 `url` 格式，就能透過 `url` 原生的 method 取得

    
    String recvString = "http://192.168.1.10:8000/login.html?key=1234567";

    try {
        URL url = new URL(recvString);
        
        logger.error("getProtocol: " + url.getProtocol());
        logger.error("getAuthority: " + url.getAuthority());
        logger.error("getHost: " + url.getHost());
        logger.error("getPort: " + url.getPort());
        logger.error("getPath: " + url.getPath());
        logger.error("getQuery: " + url.getQuery());
        logger.error("getFile: " + url.getFile());
        logger.error("getRef: " + url.getRef());


    } catch (MalformedURLException e) {
        logger.error(String.valueOf(e));
    }

getProtocol: http
getAuthority: 192.168.1.10:8000
getHost: 192.168.1.10
getPort: 8000
getPath: /login.html
getQuery: key=1234567
getFile: /login.html?key=1234567
getRef: null

## Ref.
[Parsing a URL](https://docs.oracle.com/javase/tutorial/networking/urls/urlInfo.html)

###### tags: `實作相關`