---
# System prepended metadata

title: 27_Remove_Element
tags: [leetcode]

---

# 27_Remove_Element
###### tags: `leetcode`
## Problem Statement
Given an array nums and a value val, remove all instances of that value in-place and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.
:::success
Clarification:

Confused why the returned value is an integer but your answer is an array?

Note that the input array is passed in by reference, which means a modification to the input array will be known to the caller as well.

Internally you can think of this:
```!
// nums is passed in by reference. (i.e., without making a copy)
int len = removeElement(nums, val);

// any modification to nums in your function would be known by the caller.
// using the length returned by your function, it prints the first len elements.
for (int i = 0; i < len; i++) {
    print(nums[i]);
}
:::

- Example 1:

> Input: nums = [3,2,2,3], val = 3
> Output: 2, nums = [2,2]
> Explanation: Your function should return length = 2, with the first two elements of nums being 2.
> It doesn't matter what you leave beyond the returned length. For example if you return 2 with nums = [2,2,3,3] or nums = [2,2,0,0], your answer will be accepted.

- Example 2:

> Input: nums = [0,1,2,2,3,0,4,2], val = 2
> Output: 5, nums = [0,1,4,0,3]
> Explanation: Your function should return length = 5, with the first five elements of nums containing 0, 1, 3, 0, and 4. Note that the order of those five elements can be arbitrary. It doesn't matter what values are set beyond the returned length.
 

- Constraints:

> 0 <= nums.length <= 100
> 0 <= nums[i] <= 50
> 0 <= val <= 100

## Solution
- Use ```erase()``` as the method for deleting the element

```cpp=
nums.erase(i);
```
:::danger
To notice, the input for ```erase()``` should be an iterator, and it should be taken care when in the ```for``` loop, where the iterator will skip an item!
:::
- In avoidance of skipping item, the loop is readjusted
```cpp=
for (vector<int>::iterator i= nums.begin(); i!= nums.end();)
    {
        if (*i== val)
        {
            nums.erase(i);
        }
        else
            i++;
    }
```
- The rest is relatively simple, skip them there