---
# System prepended metadata

title: LeetCode 58.Length of Last Word
tags: [String]

---

###### tags: `String`

# LeetCode 58.Length of Last Word

Given a string ```s``` consisting of words and spaces, return the length of the last word in the string.

A word is a maximal
substring
consisting of non-space characters only.  
  
 

>Example 1:
```
Input: s = "Hello World"
Output: 5
Explanation: The last word is "World" with length 5.
```
>Example 2:
```
Input: s = "   fly me   to   the moon  "
Output: 4
Explanation: The last word is "moon" with length 4.
```
>Example 3:
```
Input: s = "luffy is still joyboy"
Output: 6
Explanation: The last word is "joyboy" with length 6.
```
 

### Constraints:

- $1 <= s.length <= 10^4$
- ```s``` consists of only English letters and spaces ```' '```.
- There will be at least one word in ```s```.
---
### Idea:
>用空白字元切割出每一個單字，然後再去看最後一個單字的長度。
### Solution:

Python:
```python=
class Solution:
    def lengthOfLastWord(self, s: str) -> int:
        s = s.split()
        return len(s[len(s)-1])
```

C++:
```cpp=
```
