--- tags: data_structure_python --- # Invert Binary Tree <img src="https://img.shields.io/badge/-easy-brightgreen"> Invert a binary tree. https://leetcode.com/problems/invert-binary-tree/ <ins>**Example:**</ins> Input: ``` 4 / \ 2 7 / \ / \ 1 3 6 9 ``` Output: ``` 4 / \ 7 2 / \ / \ 9 6 3 1 ``` # Solution ```python= # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def invertTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]: def dfs(node): if node == None: return None dfs(node.left) dfs(node.right) tmp = node.left node.left = node.right node.right = tmp return node return dfs(root) ``` ```python= class Solution: def invertTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]: def dfs(node): if node == None: return None tmp_left = node.left node.left = dfs(node.right) node.right = dfs(tmp_left) return node return dfs(root) ```