---
# System prepended metadata

title: 'Delete Node in a Linked List <img src="https://img.shields.io/badge/-easy-brightgreen">'
tags: [data_structure_python]

---

---
tags: data_structure_python
---

# Delete Node in a Linked List <img src="https://img.shields.io/badge/-easy-brightgreen">

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Given linked list -- head = [4,5,1,9], which looks like following:

![](https://assets.leetcode.com/uploads/2018/12/28/237_example.png)

**Example 1:**

```
Input: head = [4,5,1,9], node = 5
Output: [4,1,9]
Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.
```

**Example 2:**

```
Input: head = [4,5,1,9], node = 1
Output: [4,5,9]
Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.
```
 
**Note:**

- The linked list will have at least two elements.
- All of the nodes' values will be unique.
- The given node will not be the tail and it will always be a valid node of the linked list.
- Do not return anything from your function.

# Solution

### Solution 1:

```python=
# Definition for singly-linked list.
class ListNode:
    def __init__(self, x):
        self.val = x
        self.next = None

class Solution:
    def deleteNode(self, node):
        """
        :type node: ListNode
        :rtype: void Do not return anything, modify node in-place instead.
        """
        while node != None:
            node.val = node.next.val
            if node.next.next == None:
                node.next = None
            node = node.next
        
```

### Solution 2:

```python=
class Solution:
    def deleteNode(self, node):
        """
        :type node: ListNode
        :rtype: void Do not return anything, modify node in-place instead.
        """
        node.val=node.next.val
        node.next=node.next.next
```