--- tags: data_structure_python --- # Get Equal Substrings Within Budget You are given two strings `s` and `t` of the same length. You want to change `s `to `t`. Changing the `i`-th character of `s` to `i`-th character of `t` costs `|s[i] - t[i]|` that is, the absolute difference between the ASCII values of the characters. You are also given an integer `maxCost`. Return the maximum length of a substring of `s` that can be changed to be the same as the corresponding substring of `t` with a cost less than or equal to `maxCost`. If there is no substring from `s` that can be changed to its corresponding substring from `t`, return `0`. **Example 1:** ``` Input: s = "abcd", t = "bcdf", maxCost = 3 Output: 3 Explanation: "abc" of s can change to "bcd". That costs 3, so the maximum length is 3. ``` **Example 2:** ``` Input: s = "abcd", t = "cdef", maxCost = 3 Output: 1 Explanation: Each character in s costs 2 to change to charactor in t, so the maximum length is 1. ``` **Example 3:** ``` Input: s = "abcd", t = "acde", maxCost = 0 Output: 1 Explanation: You can't make any change, so the maximum length is 1. ``` # Solution ### Solution 1: Sliding window (Dynamic) ```python= class Solution: def equalSubstring(self, s: str, t: str, maxCost: int) -> int: # Time complexity: O(n). # Space complexity: O(1). beg, end, m = 0, 0, len(s) cost, maxi = 0, 0 while end < m: cost += abs(ord(s[end]) - ord(t[end])) while cost > maxCost: cost -= abs(ord(s[beg]) - ord(t[beg])) beg += 1 maxi = max(maxi, end-beg+1) end += 1 return maxi ```