---
title: 'UVa 483 題解 — C++'
disqus: hackmd
---

# UVa 483 題解 — C++
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:bulb: 此筆記為UVa 483的題目詳解，包含解題思路、C++範例程式碼。
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## Word Scramble (OnlineJudge 483.)
### [題目](https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&category=0&problem=424)
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Write a program that will reverse the letters in each of a sequence of words while preserving the order of the words themselves.
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### 輸入 / 輸出說明
| **輸入說明** | **輸出說明** |
|:-|:-|
| The input file will consist of several lines of several words. Words are contiguous stretches of printable characters delimited by white space. | The output will consist of the same lines and words as the input file. However, the letters within eachword must be reversed. |

### 解題思路
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這邊我不使用字串(string)而是字元陣列代替，基本上可以將字元陣列與字串看為同樣的東西，並且題目句子包含空格，因此要使用 cin.getline(str, 1000) 讀取整行，直到換行才會結束。

接著我透過 strtok 去分割字串，以空格為分界，然後將分割後的字串由後往前輸出，即可顛倒輸出。
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### 範例程式碼

#include <bits/stdc++.h>
using namespace std;

int main()
{
	char str[1000];
	int len;
	
	while (cin.getline(str, 1000)) {
		
		char *token = strtok(str, " ");
		
		while (token != NULL) {
			len = strlen(token);
			
			for (int i=len-1;i>=0;i--)
				cout << token[i];
			
			token = strtok(NULL, " ");
			
			if (token != NULL)
				cout << " ";
		}
		
		cout << endl;
	}

	return 0;
}

### 運行結果
<font color="#00BB00">**AC**</font> 0.000s

###### tags: `CPE ?星`

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查看更多資訊請至：https://www.tseng-school.com/
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