# 7 kyu Filter the number 將字串中的數字篩選出來 暴力解,比較差的方法,先做一個數字的字串,再把字元一個一個比對 效率不好:時間複雜度應該是 O(n**2)兩層迴圈 ```javascript= var filterString = function(value) { let charArr = value.split('') let number = '0123456789' let newString = '' charArr.forEach( char => { if (number.includes(char)) { newString += char } }) return Number(newString) } ```