# Bi-amonds

## Problem Description
> Create a diamond composed of 1s and 0s with an alternating pattern from the perimeter going towards the center of the diamond. Expect all the test cases to be odd numbers.

###### Input Sample
7
###### Output Sample

   1
  101
 10101
1010101
 10101
  101
   1

## Solution
> The pattern can only be printed out properly using odd numbers so when making test cases, make sure the test input is odd.

import java.util.Scanner;

//code only works for odd inputs

public class pattern2 {

	public static void main(String[] args) {
		Scanner input = new Scanner(System.in);
		int x = input.nextInt();
		
		for(int i = 0, num = 0; i < x; i++ ) {
			if(i < (x/2)) {
				for(int j = 0; j < (x/2)-i; j++) {
					System.out.print(" ");
				}
				for(int j = 0; j <= num; j++) {
					if(j%2 == 0 && j == num)
						System.out.println("1");
					else if(j%2 == 0)
						System.out.print("1");
					else
						System.out.print("0");
				}
				num+=2;
			}
			if(i >= (x/2)) {
				for(int j = 0; j < i-(x/2); j++) {
					System.out.print(" ");
				}
				for(int j = 0; j <= num; j++) {
					if(j%2 == 0 && j == num)
						System.out.println("1");
					else if(j%2 == 0)
						System.out.print("1");
					else
						System.out.print("0");
				}
				num-=2;
			}
		}
		input.close();
	}

}