# 2023q1 Homework (quiz1) contributed by <`ctfish7063`> ## 測驗`1` ## 測驗`2` ## 測驗`3` XOR 運算特性: 程式碼列表: ```c #include <assert.h> #include <errno.h> #include <stddef.h> #include <stdint.h> #include <stdio.h> #include <stdlib.h> /** * struct _xorlist_node - node of xor list * @cmp: the encrypted pointer of prev and next pointers * * The cmp is obtained by xor of address of the two * neighboring nodes. */ typedef struct _xorlist_node { struct _xorlist_node *cmp; } xor_node_t; /** * struct _xor_list_struct - the xor list * @head: pointer to the head node of list * @tail: pointer to the tail node of list * @count: the number of node in list */ typedef struct _xor_list_struct { xor_node_t head, tail; uint32_t count; } xor_list_t; /** * XOR_COMP - the xor operation * @a: pointer to do xor * @b: pointer to do xor */ #define XOR_COMP(a, b) ((xor_node_t *) (LLLL)) /** * xor_node_t* address_of - do xor of two input pointer * @n1: pointer to previous node * @n2: pointer to next node * * This function first validate the two input pointers, * then will it do the actual xor operation by calling * the XOR_COMP macro. */ static inline xor_node_t *address_of(xor_node_t *n1, xor_node_t *n2) { assert(n1 && n2); return XOR_COMP(n1, n2); } /** * container_of - obtain structure containing member * @ptr: pointer to member * @type: type of desire structure * @member: member belonging to the desire structure * */ #define container_of(ptr, type, member) \ __extension__({ \ const __typeof__(((type *) 0)->member) *__pmember = (ptr); \ (type *) ((char *) __pmember - offsetof(type, member)); \ }) /** * xorlist_for_each * */ #define xorlist_for_each(node, rp, rn, list) \ for (rp = &(list)->head, node = rp->cmp; node != &(list)->tail; \ rn = address_of(rp, node->cmp), rp = node, node = rn) #define xorlist_for_each_prev(node, rp, rn, list) \ for (rp = &(list)->tail, node = rp->cmp; node != &(list)->head; \ rn = address_of(rp, node->cmp), rp = node, node = rn) #define xorlist_for_each_from(node, pos1, pos2, rp, rn, list) \ for (rp = pos2, node = pos1; node != &(list)->tail; \ rn = address_of(rp, node->cmp), rp = node, node = rn) #define xorlist_for_each_from_prev(node, pos1, pos2, rp, rn, list) \ for (rp = pos1, node = pos2; node != &(list)->head; \ rn = address_of(rp, node->cmp), rp = node, node = rn) /* Note that when the delete function success is must return 0. */ #define xorlist_delete_prototype(name, node) \ int _xorlist_delete_##name(xor_node_t *node) #define xorlist_delete_call(name) _xorlist_delete_##name static inline xor_node_t *xornode_init(xor_node_t *n) { assert(n); n->cmp = NULL; return n; } #define XORNODE_INIT(n) \ do { \ (n).cmp = NULL; \ } while (0) #define XORLIST_INIT(h) \ do { \ (h).head.cmp = &(h).tail; \ (h).tail.cmp = &(h).head; \ (h).count = 0; \ } while (0) int xorlist_add(xor_list_t *list, xor_node_t *n) { xor_node_t *real_next; if (!n) return ENOMEM; xor_node_t *real_prev = &list->head; xor_node_t *node = real_prev->cmp; if (node == &list->tail) real_next = MMMM; else real_next = node; real_prev->cmp = n; n->cmp = XOR_COMP(real_prev, real_next); real_next->cmp = XOR_COMP(n, XOR_COMP(real_prev, PPPP)); list->count++; return 0; } int xorlist_del(xor_list_t *list, xor_node_t *n, xor_node_t *target, int (*delete_func)(xor_node_t *)) { assert(list && n && target && delete_func); assert(&list->head != target && &list->tail != target); xor_node_t *nn = address_of(target, n->cmp); xor_node_t *an = address_of(n, target->cmp); xor_node_t *ana = address_of(target, an->cmp); n->cmp = XOR_COMP(nn, an); an->cmp = XOR_COMP(n, ana); delete_func(target); list->count--; return 0; } int xorlist_destroy(xor_list_t *list, int (*delete_func)(xor_node_t *)) { assert(delete_func); xor_node_t *real_prev = &list->head; xor_node_t *node = real_prev->cmp; xor_node_t *real_next = address_of(real_prev, node->cmp); xor_node_t *tmp = real_prev; real_prev = node; node = real_next; while (node != &list->tail) { real_next = address_of(real_prev, node->cmp); tmp = real_prev; real_prev = node; node = real_next; if (delete_func(tmp) != 0) perror("delete function failed"); } return 0; } struct test_node { int value; xor_node_t xornode; }; xorlist_delete_prototype(test_delete, _node) { struct test_node *node = container_of(_node, struct test_node, xornode); free(node); return 0; } int main(void) { xor_list_t list; xor_node_t *p1, *p2; XORLIST_INIT(list); for (int i = 0; i < 1000; i++) { struct test_node *new = malloc(sizeof(struct test_node)); xornode_init(&new->xornode); new->value = i; xorlist_add(&list, &new->xornode); if (i == 5) p1 = &new->xornode; if (i == 6) p2 = &new->xornode; } xor_node_t *real_prev, *real_next, *node; int i = 0; printf("xorlist_for_each test\n"); xorlist_for_each(node, real_prev, real_next, &list) { printf("node [%d] %d\n", i++, container_of(node, struct test_node, xornode)->value); } i = 0; printf("xorlist_for_from test\n"); xorlist_for_each_from(node, p1, p2, real_prev, real_next, &list) { printf("node %d\n", container_of(node, struct test_node, xornode)->value); } i = 0; printf("xorlist_for_each_from_prev test\n"); xorlist_for_each_from_prev(node, p1, p2, real_prev, real_next, &list) { printf("node [%d] %d\n", i++, container_of(node, struct test_node, xornode)->value); } i = 0; printf("xorlist_for_each_prev test\n"); xorlist_for_each_prev(node, real_prev, real_next, &list) { printf("node [%d] %d\n", i++, container_of(node, struct test_node, xornode)->value); } printf("xorlist_del test\n"); xorlist_del(&list, p2, p1, xorlist_delete_call(test_delete)); i = 0; xorlist_for_each(node, real_prev, real_next, &list) { printf("node [%d] %d\n", i++, container_of(node, struct test_node, xornode)->value); } xorlist_destroy(&list, xorlist_delete_call(test_delete)); return 0; } ``` 請補完程式碼,使其運作符合預期。作答規範: - [x] LLLL 為表示式,在運算子前後要一個空白字元區隔,應包含 uintptr_t,符合 lab0-c 預期的排版風格 - [X] MMMM 和 PPPP 為表示式 ::: success 延伸問題: 解釋上述程式碼運作原理,指出其實作缺陷並改進 在上述 XOR linked list 的基礎,實作測驗 `1` 和 `2` 提及的快速排序演算法,注意要引入你改進效能的版本 改進 `xorlist_destroy`,使其不急著釋放記憶體,而是在 `atexit` 之際處理 ::: ### 作答 LLLL=(uintptr_t) a ^(uintptr_t) b MMMM=&list->tail PPPP=real_next->cmp