# 2443. Sum of Number and Its Reverse
###### tags: `Leetcode` `Medium`
Link: https://leetcode.com/problems/sum-of-number-and-its-reverse/description/
## 思路
暴力解
有一个小tricky是可以把遍历的范围改成num/2到num
注意不能改成0到num/2
因为如果num=181 答案是041+140
如果我们遍历0到num/2我们只会碰到41 但是41+14=55 不会碰到140
## Code

class Solution {
    public boolean sumOfNumberAndReverse(int num) {
        for(int i=0; i<=num; i++){
            if(i+reverse(i)==num) return true;
        }
        return false;
    }
    private int reverse(int num){
        StringBuilder sb = new StringBuilder(String.valueOf(num));
        return Integer.valueOf(sb.reverse().toString());
    }
}