# 2460. Apply Operations to an Array
###### tags: `Leetcode` `Easy` `Two Pointers`
Link: https://leetcode.com/problems/apply-operations-to-an-array/description/
## 思路 $O(N)$ $O(1)$
首先brute force 如果```nums[i]==nums[i+1]```, ```nums[i]*=2;``` ```nums[i+1]=0;```
然后用双指针shift 0
## Code

class Solution {
    public int[] applyOperations(int[] nums) {
        for(int i=0; i<nums.length-1; i++){
            if(nums[i]==nums[i+1]){
                nums[i]*=2;
                nums[i+1]=0;
            }
        }
        int p1=0, p2=0;
        for(p1=0; p1<nums.length; p1++){
            if(nums[p1]!=0){
                nums[p2++] = nums[p1];
            }
        }
        while(p2<nums.length){
            nums[p2++] = 0;
        }
        return nums;
    }
}