# 0024. Swap Nodes in Pairs
###### tags: `Leetcode` `Medium` `Linked List`
Link: https://leetcode.com/problems/swap-nodes-in-pairs/
## 思路
### 思路一
遍历,两两一组做交换
### 思路二
递归(感觉linked list的题蛮多用递归做的)
## Code
### 思路一
```c=
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* swapPairs(ListNode* head) {
ListNode* dummy = new ListNode;
dummy->next = head;
head = dummy;
while(head->next!=nullptr&&head->next->next!=nullptr){
ListNode* temp1 = head->next;
ListNode* temp2 = head->next->next;
head->next = temp2;
temp1->next = temp2->next;
temp2->next = temp1;
head = temp1;
}
return dummy->next;
}
};
```
### 思路二
```c=
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* swapPairs(ListNode* head) {
if(head == nullptr || head->next == nullptr){
return head;
}
ListNode* newHead = head->next;
head->next = swapPairs(newHead->next);
newHead->next = head;
return newHead;
}
};
```
## Result
### 思路一
Runtime: 4 ms, faster than **57.37%** of C++ online submissions for Swap Nodes in Pairs.
Memory Usage: 7.6 MB, less than **45.78%** of C++ online submissions for Swap Nodes in Pairs.
### 思路二
Runtime: 0 ms, faster than **100.00%** of C++ online submissions for Swap Nodes in Pairs.
Memory Usage: 7.6 MB, less than **45.78%** of C++ online submissions for Swap Nodes in Pairs.