# \#412 Fizz Buzz
## *回傳一字串陣列, 當陣列索引+1為3的倍數時='Fizz', 為5的倍數時='Buzz', 為15的倍數時='FizzBuzz', 其餘情況為索引值*
## Log
- build 20210809 by syhuang

## 另解
- 不使用取餘數, 改用變數歸零方法, 但實際沒比較快
- leetcode submit runtime 60%, memory 60%

var fizzBuzz = function(n) {
    let Fizz = 0, Buzz = 0;
    let result = [];
    for(let i=0; i<n; i++){
        Fizz++,Buzz++;
        if(Fizz==3 && Buzz==5){
            result.push('FizzBuzz');
            Fizz=0, Buzz=0;
        }else if(Fizz==3){
            result.push('Fizz');
            Fizz=0;
        }else if(Buzz==5){
            result.push('Buzz');
            Buzz=0;
        }else result.push((i+1).toString());
    }
    return result;
};

## 初見
- 迴圈+取餘數
- leetcode submit runtime 60%, memory 30%

var fizzBuzz = function(n) {
    let result = [];
    for(let i=0; i<n; i++){
        if((i+1)%15==0) result.push('FizzBuzz');
        else if((i+1)%3==0) result.push('Fizz');
        else if((i+1)%5==0) result.push('Buzz');
        else result.push((i+1).toString());
    }
    return result;
};

## 備註
## 參考
- [參考解](https://leetcode.com/problems/fizz-buzz/discuss/89931/Java-4ms-solution-Not-using-%22%22-operation)
###### tags: `leetcode`, `leetcode-easy`