# \#182 Duplicate Emails
## *找出table內重複出現的eamil*
## Log
- build 20210417 by syhuang

## 初見
- group+having基本用法

select Email from(
select count(Id), Email
  from Person
 group by Email
having count(Id) > 1) t

## 備註
- 初見即畢業
## 參考
###### tags: `leetcode`, `leetcode-easy`, `sql`